Trigonometrical Ratios of Standard Angles Test

Result

Trigonometrical Ratios of Standard Angles Test - 5

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Weekly Quiz Competition

Question 1
1 / -0

Solve for , if 2 tan - sec - (2 sin - 1) = 0, where 0 < < 90^o.

A
0 or 30^o

B
30^o or 45^o

C
45^o or 60^o

D
60^o or 90^o

E
45^o or 90^o
Question 2
1 / -0

Find the value of cos 22.5^o cos 67.5^o – sin 22.5^o sin 67.5^o.

A
1

B

C

D
0
Question 3
1 / -0

If sin (2B - A) = 2 sin (3A - B) = , find the value of 2A - B.

A
1

B
0

C
80^o

D
90^o
Question 4
1 / -0

If sin² - 3 cos² = 0, find the value of 2 tan² - sec + 3 and acute angle .

A
4, 30^o

B
6, 90^o

C
7, 60^o

D
2, 45^o

E
None of these
Question 5
1 / -0

If 3 - 3 cos A - 2 sin² A = 0, then the measure of angle A is

A
0^o or 45^o

B
30^o or 60^o

C
60^o or 45^o

D
0^o or 60^o
Question 6
1 / -0

^{_{If 10 sin}_{= 6, then tan}_{+ cot}₌}

A

B

C

D
Question 7
1 / -0

Find the value of sin 50^o cos 40^o + cos 50^o sin 40^o.

A
0

B
– 1

C
1

D
1/2
Question 8
1 / -0

If sec (A - B) = cosec (A + B) = , then the measures of A and B respectively are

A
45^o, 15^o

B
45^o, 45^o

C
15^o, 45^o

D
None of these
Question 9
1 / -0

If tan²x = 1, then sin 2x is

A
1

B

C

D
Question 10
1 / -0

If A = 15^o, then the value of tan 2A ^.cos 3A ^.sin 4A is

A

B

C

D
Question 11
1 / -0

If cos²60^o + cos² (x + 30)^o = 1 and 0 , the value of `x` is

A
180^o

B
90^o

C
45^o

D
0^o
Question 12
1 / -0

If tan + cot = 3, then tan² + cot² is equal to

A
9

B
12

C
7

D
1
Question 13
1 / -0

If cos² 45 + cos²x = 1, the measure of x is

A
90^o

B
0^o

C
45^o

D
60^o
Question 14
1 / -0

If cos 6x = 0 and x is acute, then sin 2x is

A

B

C

D
0