HCF And LCM of Numbers Test-3

Result

HCF And LCM of Numbers Test-3

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Weekly Quiz Competition

Question 1
1 / -0.25

If the product of two numbers is 2496 and HCF is 8,then the ratio of HCF and LCM is

A
1:32

B
39:1

C
1:39

D
4:63

E
None of these

Solution

HCF = 8
LCM = Product/HCF Product of the 2 number = 2496
HCF:LCM = 8 : (2496/8) ⇒8 : 312 ⇒1: 39
Question 2
1 / -0.25

The greatest possible length which can be used to measure exactly the lengths 1m 92cm,3m 84cm ,23m 4cm

A
23

B
32

C
36

D
34

E
None of these

Solution

192 = 4² ×2² ×3
384 = 4² ×2² ×6
2304 = 4² ×2 ×6²
HCF = 4² ×2 = 16 ×2 = 32
Question 3
1 / -0.25

HCF of 4/3, 8/6, 36/63 and 20/42

A
4/126

B
4/8

C
4/36

D
4/42

E
None of these

Solution

HCF of numerator(4,8,36,20) = 4
LCM of denominator(3,6,63,42) = 126
Question 4
1 / -0.25

Find the LCM of 3/8, 9/32, 33/48, 18/72

A
3/8

B
8/33

C
198/8

D
8/3

E
None of these

Solution

LCM of numerator(3,9,33,18) = 198
HCF of denominator(8,32,48,72) = 8
Question 5
1 / -0.25

The HCF of 2511 and 3402 is

A
31

B
42

C
76

D
81

E
None of these

Solution

2511 = 81 ×31
3402 = 81 ×42
Hence HCF is 81
Question 6
1 / -0.25

A gardener had a number of shrubs to plant in rows. At first he tried to plant 8,then 12 and then 16 in a row but he had always 3 shrubs left with him. On trying 7 he had none left. Find the total number of shrubs.

A
154

B
147

C
137

D
150

E
None of these

Solution
Question 7
1 / -0.25

If m and n are two whole numbers and if mⁿ = 49. Find n^m, given that n ≠1

A
118

B
94

C
561

D
128

E
None of these

Solution

49 = 7² = mⁿ
n^m = 2⁷ = 128
Question 8
1 / -0.25

What will be the least number which when doubled will be exactly divisible by 12,18,21 and 30?

A
630

B
360

C
603

D
306

E
None of these

Solution

LCM of 12,18,21 and 30 = 1260
Doubled (divide by 2) = 1260/2 = 630
Question 9
1 / -0.25

HCF and LCM of two numbers are 11 and 385 .If one number lies between 75 and 125 then that number is

A
123

B
73

C
77

D
154

E
None of these

Solution

Product of the two number = 11a ×11b = 4235
11a ×11ab = 4235/121 = 35
35 = 7 ×5 (co prime)
77 ×11 = 77
Question 10
1 / -0.25

If the L.C.M of x and y is z, their H.C.F is

A
xy/z

B
xyz

C
(x + y)/z

D
z/xy

E
None of these

Solution

HCF = Product of the 2 number/LCM = XY/Z

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Re-Attempt Weekly Quiz Competition

HCF And LCM of Numbers Test-3

Result

HCF And LCM of Numbers Test-3

Score

-

Rank

-

SHARING IS CARING

Question 1

1:32

39:1

1:39

4:63

None of these

Solution

Question 2

23

32

36

34

None of these

Solution

Question 3

4/126

4/8

4/36

4/42

None of these

Solution

Question 4

3/8

8/33

198/8

8/3

None of these

Solution

Question 5

31

42

76

81

None of these

Solution

Question 6

154

147

137

150

None of these

Solution

Question 7

118

94

561

128

None of these

Solution

Question 8

630

360

603

306

None of these

Solution

Question 9

123

73

77

154

None of these

Solution

Question 10

xy/z

xyz

(x + y)/z

z/xy

None of these

Solution

User

Question Analysis