Quantitative Techniques Test-3

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Quantitative Techniques Test-3

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Question 1
1 / -0.25

In a class average age of 24 boys and their teacher is 15 years. When the teacher 's age is excluded the average age decreases by one year. The age of the teacher is?

A
40

B
39

C
38

D
41

Solution

Sum of the ages of 24 boys and 1 teacher = (15 x 25) years = 375 years.
Sum of the ages of 24 boys = (24 x 14) years = 336 years.
Age of the teacher = (375 −336) years = 39 years.
Question 2
1 / -0.25

The monthly income of P and Q are in ratio 2:3 and their monthly expenses are in ratio 5:9. If each of them save 300 per month, their monthly income is:

A
800, 1200

B
1200, 800

C
400, 1200

D
800, 2400

Solution

Income of A = 2x
Income of B = 3x
Savings of A = 300
Savings of B = 300
Monthly expense are in ratio 5:9
(2x-300) / (3x-300) = 5/9
⇒ 18x - 2700 = 15x - 1500
⇒ 3x = 1200
⇒ x = 400
Therefore,
Income of A = 2x = 2 * 400 = 800
Income of B = 3x = 3 * 400 = 1200
Question 3
1 / -0.25

Man covers a certain distance by driving a car at the speed of 60 km/h and return back to the starting point at the speed of 40 km/h. Find its average speed?

A
48 km/h

B
51 km/h

C
50 km/h

D
42 km/h

Solution
Question 4
1 / -0.25

Two numbers are such that the ratio between them is 3:4 but if each is increased by 3 then the ratio becomes 4:5. Find the difference between the numbers?

A
3

B
9

C
2

D
7

Solution

Let the two numbers be 3x, 4x

⇒15x + 15 = 16x + 12
⇒x = 3
Diff = (4*3) - (3*3) = 3
Question 5
1 / -0.25

At present, the age of the father is five times that the age of the son. Three years hence, the father 's age would be four times that of his son. Find the present age of the father and the son?

A
8,40

B
7,49

C
5,35

D
9,45

Solution

Let the son 's age be x.
⇒Father 's age = 5x

⇒5x + 3 = 4x + 12
⇒x = 9
Hence, son 's age is 9 and father 's age is 45.
Question 6
1 / -0.25

If 25% of a number is 65, then 45% of the number will be?

A
128

B
107

C
149

D
117

Solution
Question 7
1 / -0.25

A and B have money in the ratio 2:1. If A gives Rs. 2 to B, the money will be in the ratio 1:1. What were the initial amounts they had?

A
Rs. 12 and Rs. 6

B
Rs. 16 and Rs. 8

C
Rs. 8 and Rs. 4

D
Rs. 6 and Rs. 3

Solution

Before lending the money, the ratio of money A and B = 2:1
After lending the money, the ratio of money A and B = 1:1
Since, A gives B two rupees

⇒2x - 2 = x + 2
⇒x = 4
A = 2 ×4 = 8, B = 1 ×4 = 4
Question 8
1 / -0.25

18 men can reap a field in 50 days. In how many days will 30 men can complete the same work?

A
90/2

B
31

C
32.5

D
30

Solution

18 * 50 = Days * 30
⇒Days = 30
Question 9
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A is working and B is sleeping partner in a firm. A invest Rs 2100 and B invests Rs 3100. A being working partner gets 25% of the profits, and the balance of the profits to be divided in the proportion to their capitals. What did each get out of profit of Rs 1040?

A
600, 440

B
575, 465

C
530, 510

D
0, 1040

Solution

Total profit = 1040.
A 's 25% profit = 1040 * 1/4 = 260
Remaining profit = 780
Ratio of investment of A and B = 2100:3100 = 21:31
Question 10
1 / -0.25

A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:

A
22

B
24

C
23

D
26

Solution

Let the number of hens be x and the number of cows be y .
Then, x + y = 48 .... (i)
and 2x + 4y = 140
⇒ x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
∴ The required answer = 26.