Matrices Test

Result

Matrices Test - 8

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Weekly Quiz Competition

Question 1
1 / -0.25

Read the following text and answer the following questions from (1 - 5) on the basis of the same:
A manufacture produces three stationery products Pencil, Eraser and Sharpener which he sells in two markets. Annual sales are indicated below
If the unit Sale price of Pencil, Eraser and Sharpener are ₹2.50, ₹1.50 and ₹1.00 respectively, and unit cost of the above three commodities are ₹2.00, ₹1.00 and ₹0.50 respectively, then,
Total revenue of market A

A
₹64,000

B
₹60,400

C
₹46,000

D
₹40600

Solution

Total revenue of
= [2.50 x 10,000 + 1.50 x 2,000 + 1.00 x 18,000]
= [46, 000]
Question 2
1 / -0.25

Total revenue of market B

A
A. ₹ 35,000

B
B. ₹ 53,000

C
C. ₹ 50,300

D
D. ₹ 30,500

Solution

Total revenue of market B
= [2.50 x 6,000 + 1.50 x 20,000 + 1,00 x 8,000]
= 53,000
Question 3
1 / -0.25

Cost incurred in market A

A
A. ₹ 13,000

B
B. ₹ 30,100

C
C. ₹ 10,300

D
D. ₹ 31,000

Solution

Cost incurred in market A
= [2.00 x 10,000 + 1.00 x 2,000 + 0.50 x 18,000]
= 31,000
Question 4
1 / -0.25

Profits in market A and B respectively are

A
A. ₹ 15,000, ₹ 17,000

B
B. ₹ 17,000, ₹ 15,000

C
C. ₹ 51,000, ₹ 71,000

D
D. ₹ 10,000, ₹ 20,000

Solution

Cost incurred in market B
= [2.00 x 6,000 + 1.00 x 20,000 + 0.58 x 8,000]
= 36,000
Profit of market A & B = total revenue of A and B – Cost increased in market A and B
i.e., (₹15,000, ₹17,000)
Question 5
1 / -0.25

Gross profit in both markets

A
A. ₹23,000

B
B. ₹20,300

C
C. ₹32,000

D
D. ₹30,200

Solution

Gross profit in both markets = Profit in A + Profit in B
= 15,000 + 17,000
= ₹32,000
Question 6
1 / -0.25

Direction: Read the following text and answer the following questions from (6 - 10) on the basis of the same:
Amit, Biraj and Chirag were given the task of creating a square matrix of order 2.
Below are the matrices created by them. A, B, C are the matrices created by Amit, Biraj and Chirag respectively.
If a = 4 and b = −2,
Sum of the matrices A, B and C, A+(B + C) is

A

B

C

D

Solution

A +B+ C =
Question 7
1 / -0.25

(A^T )^T is equal to

A
A.

B
B.

C
C.

D
D.

Solution
Question 8
1 / -0.25

(bA)^T is equal to

A
A.

B
B.

C
C.

D
D.

Solution
Question 9
1 / -0.25

AC − BC is equal to

A
A.

B
B.

C
C.

D
D.

Solution

AC-BC =
Question 10
1 / -0.25

(a + b)B is equal to

A
A.

B
B.

C
C.

D
D.

Solution

( a +b)B= (4 - 2)
Question 11
1 / -0.25

Direction: Read the following text and answer the following questions from (11 - 15) on the basis of the same:
Three schools DPS, CVC and KVS decided to organize a fair for collecting money for helping the flood victims. They sold handmade fans, mats and plates from recycled material at a cost of ₹25, ₹100 and ₹50 each respectively. The numbers of articles sold are given as
What is the total money (in Rupees) collected by the school DPS?

A
700

B
7,000

C
6,125

D
7,875

Solution

The funds collected by the schools can be obtained by matrix multiplication
Funds collected by school DPS = 7000
Funds collected by school, CVC = 6125
Funds collected by school KVS = 7875
Question 12
1 / -0.25

Three schools DPS, CVC and KVS decided to organize a fair for collecting money for helping the flood victims. They sold handmade fans, mats and plates from recycled material at a cost of Rs. 25, Rs.100 and Rs. 50 each respectively. The numbers of articles sold are given as
What is the total amount of money (in ₹) collected by schools CVC and KVS?

A
14,000

B
15,725

C
21,000

D
13,125

Solution

Total amount of money collected by school
= 6125 + 7875
= 14000
Question 13
1 / -0.25

What is the total amount of money collected by all three schools DPS, CVC and KVS?

A
A. ₹15,775

B
B. ₹14,000

C
C. ₹21,000

D
D. ₹17,125

Solution

Total amount of money collected by all school DPS, CVC and KVS
= 7000 + 7875 + 6125
= 21000
Question 14
1 / -0.25

If the number of handmade fans and plates are interchanged for all the schools, then what is the total money collected by all schools?

A
₹18,000

B
₹6,750

C
₹5,000

D
₹21,250

Solution

If the number of handmade fans and plates are interchanged for all the schools, then our table will look like
Let our new matrix be A

An, our sale price of articles is denoted by matrix Y

Now,
Total Revenue = Sales price x Total sales
= YA

Total amount collected by all 3 school = Rs. 7500 + 6000 + 7750
= Rs 21, 250
Question 15
1 / -0.25

How many articles (in total) are sold by three schools?

A
A. 230

B
B. 130

C
C. 430

D
D. 330

Solution

Total Articles sold = (40 + 25 + 35) + (50 + 40 + 50) + (20 + 30 + 40)
= 100 + 140 + 90
= 330