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Continuity and Differentiability Test - 5

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Continuity and Differentiability Test - 5
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  • Question 1
    1 / -0.25

    The dervative of y  

  • Question 2
    1 / -0.25

    Differentiate   with respect to x.

    Solution

    y = e^(-x)2 .................(1)
    Put u = (-x)2
    du/dx = -2x dx
    Differentiating eq(1) y = eu
    dy/du = e^u
    ⇒dy/dx = (dy/du) * (du/dx)
    = (eu ) * (-2x)
    ⇒- 2xe(-x2)

  • Question 3
    1 / -0.25

    The  derivatve of f(x) = 

    Solution

    f(x) =   elog(logx3)
    As log and e are inverse operations, therefore
    f(x)= logx3
    So derivative will be             {Derivative of log x is 1/x and then applying chain rule}

    f ’(x)=1/x3 . 3x2   = 3/x

  • Question 4
    1 / -0.25

    The sum of Which series is denoted by e.

  • Question 5
    1 / -0.25

    Derivatve of f(x)  is given by

    Solution

     y
    The derivative of y = ef(x) is dy/dx = f '(x)ef(x)
    In this case, f(x) = x2 , and the derivative of x2 = 2x
    Therefore, f '(x)= 2x,
     dy/dx = 2x

  • Question 6
    1 / -0.25

    The differential equation of y = 

  • Question 7
    1 / -0.25

    If f(x) = e2x-5 , then f '(x) is ​

  • Question 8
    1 / -0.25

    Whta is the derivatve of y = log5  (x)

    Solution

    y = log5 x = ln x/ln 5 →change of base  
    = ln x/ln 5
    dy/dx = 1/ln5 ⋅1/x →1/ln5 is a constant, so we don 't change it
    = 1/(x ln 5)

  • Question 9
    1 / -0.25

    For what values of x is elogx  = x

    Solution

    The correct option is A
    Set of all positive real numbers

  • Question 10
    1 / -0.25

    If f(x) = ex , then the value of f '(-3) is

    Solution

    As, f (x) = ex
    Similarly, f (-3) = e-3

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