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Three-dimensional Geometry Test - 6

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Three-dimensional Geometry Test - 6
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  • Question 1
    1 / -0.25

    Let    be the position vector of an arbitrary point P(x, y, z). Cartesian form of the equation of line passes through two points (x1 , y1 , z1 ) and (x2 , y2 , z2 ) is:

  • Question 2
    1 / -0.25

    Find the vector equation of the line that passes through the origin and (-6,2,1).

  • Question 3
    1 / -0.25

    The Cartesian equation of the line which passes through the point (2, -2, -1) and parallel to the line   , is given by

  • Question 4
    1 / -0.25

    If the vector equation of a line is   find its caryesian equation.

    Solution

    r = -2i + 3j + 7k + λ( -i - 2j - 3k)
    xi + yj + zk = (-2-λ)i + (3-2 λ)j + (7-3 λ)k
    Equating the terms, we get
    x = -2-λ  y = 3-2 λ z = 7-3 λ
    (x+2)/(-1) = λ,  (y-3)/(-2) = λ,   (z-7)/(-3) = λ
    (x+2)/(1) =  (y-3)/(2) =  (z-7)/(3) 

  • Question 5
    1 / -0.25

    The vector form of the equation is. The Cartesian equation of the line is:

  • Question 6
    1 / -0.25

    Let the coordinates of the given point A be (x1 , y1 , z1 ) and the direction ratios of the line be a, b, c. If the co-ordinates of any point P is (x, y, z), then the equation of the line in Cartesian form is:

  • Question 7
    1 / -0.25

    Let    be a position vector of A with respect to the origin O and    be a position vector of an arbitrary point. The equation of line which passes through A and parallel to a vector   is:

     

  • Question 8
    1 / -0.25

    The Cartesian equation of the line passing through the points (-3, 1, 0) and (1, 2, 3) is:

  • Question 9
    1 / -0.25

    The Cartesian equation of the line which passes through the origin and parallel to the line   , is given by

  • Question 10
    1 / -0.25

    Find the Cartesian equation of the line that passes through the point (-3,-4,-2) and (3,4,2).

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