Download CBSE Sample Paper 2024-25 for class 12th to 8th

Mix Test - 8

Result

Mix Test - 8

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Question 1
1 / -0.25

In how many years will the sum of money double itself at 10% per annum S.I. ?

A
10 years

B
4 years

C
5 years

D
8 years

Solution
Question 2
1 / -0.25

There are 20 girls and 15 boys in a class. What is the ratio of the number of girls to the total number of students in the class?

A
It is 7:4

B
It is 4:7

C
It is 4:3

D
It is 3:4

Solution

Total students= 20 + 15 = 35
ratio = no. of girls: total students
= 20:35
Question 3
1 / -0.25

Express 256,000,000 in the expanded form.

A
2 × 10⁸ + 5 × 10⁷ + 6 × 10⁴

B
2 × 10⁸ + 5 × 10⁷ + 6 × 10³

C
2 × 10⁸ + 5 × 10⁷ + 6 × 10⁶

D
2 × 10⁸ + 5 × 10⁷ + 6 × 10⁵
Question 4
1 / -0.25

The list price of a shirt is Rs 300. A discount of 12% is announced on sales. What is the amount of discount on it?

A
Rs 36

B
Rs 30

C
None of these

D
Rs 33

Solution
Question 5
1 / -0.25

Standard gold contains 22 parts of pure gold to 2 parts of alloy. The percentage of alloy in a sovereign which is made of standard gold is:

A
8 1/3%

B
11 1/3%

C
12%

D
11%

Solution

Total parts = 22 parts + 2 parts = 24 parts

24 parts contain 2 parts alloy

∴ 100 parts contain 2/24 × 100 = 25/3 = 8 1/3%.
Question 6
1 / -0.25

The value of [3**3]**4 is:

A
54

B
36

C
60

D
68

Solution

[3∗∗3]∗∗4=[(3+2)×3]∗∗4=15∗∗4=[15+2]×4=68.
Question 7
1 / -0.25

The value of [1*2]* 3 is :

A
7

B
9

C
11

D
5

Solution

[1∗2]∗3=[1+2×2[∗3=5∗3=5+3×2=11
Question 8
1 / -0.25

A number 'x' when multiplied by 5 and added to three times its own gives 64, the number is:

A
8

B
14

C
12

D
18

Solution

The answer is Direct proportion as in direct proportion two quantities increase or decrease together to keep the ratio of corresponding value constant.
Question 9
1 / -0.25

Find the number from the following expanded form: 8 × 10⁴ + 6 × 10³ + 0 × 10² + 4 × 10¹ + 5 × 10⁰

A
86045

B
80045

C
96045

D
86054

Solution

80000 + 6000 + 0 + 40 + 5 = 86045
Question 10
1 / -0.25

The value of [5**0]**3 is:

A
0

B
21

C
6

D
15

Solution

[5∗∗3]∗∗3=[(5+2)×0]∗∗3=0∗∗3=[0+2]×3=6