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Time Speed Distances And Time & Work Test - 1

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Time Speed Distances And Time & Work Test - 1
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  • Question 1
    1 / -0.25

    A can do a piece of work in 7 days of 9 hr each, and B can do it in 6 days of 7 hr each. How long will they take to do it working together 42/5 hr a day?

    Solution

    A takes 7 × 9 = 63 hr.

    ∴ In 1 hr A does 1/63 of work.

    B takes 6 × 7 = 42 hr.

    ∴ In 1 hr B does 1/42 of work.

     

  • Question 2
    1 / -0.25

    A can do a piece of work in 80 days. He works for 10 days and then B alone finishes the remaining work in 42 days. The two together could complete the work in

    Solution

     

  • Question 3
    1 / -0.25

    A and B can do a piece of work in 45 and 40 days respectively. They begin together, but A leaves after some days and B completes the remaining work in 23 days. For how many days did A work?

    Solution

    B’s work lasts 23 days.

    ∴ Work done in 23 days by B = 23/40.

     

  • Question 4
    1 / -0.25

    A does half as much as work as B in three-fourths of the time. If together they take 18 days to complete the work, how much time will B take to do it?

    Solution

    Work done A : B = 1 : 2.

    Time taken A : B = 3 : 4.

    ∴ A works 1 unit in 3 hr.

    ∴ In 1 hr = 1/3 unit of work.

     

  • Question 5
    1 / -0.25

    A can do a certain job in 12 days. B is 60% more efficient than A. B can do the work alone in

    Solution

    A : B work done in same time = 10 : 16 = 5 : 8.

    (As B is 60% more efficient).

     

  • Question 6
    1 / -0.25

    A and B can do a job in 25 days and 20 days respectively. A started the work and was joined by B after 10 days. The number of days taken to complete the work is

    Solution

     

  • Question 7
    1 / -0.25

    A is twice as good as B, and they together finish a job in 14 days. A will finish the work alone in

    Solution

    Let A can finish a job in x days and B can do it in 2x days

     

  • Question 8
    1 / -0.25

    A and B can do a piece of work in 72 days; B and C in 120 days; A and C in 90 days. In how many days can A do it alone?

    Solution

    A + B = 72 days, B + C = 120 days, A + C = 90 days.

    Assume units of work = 360 = [(LCM(72, 120, 90)].

     

  • Question 9
    1 / -0.25

    A and B can do a job in 12 days, and B and C can do it in 16 days. After A has been working for 5 days and B for 7 days, C finishes the work in 13 days. In how many days can C do the work alone?

    Solution

    Assume a units of work = LCM of (12, 16) = 48.

     

  • Question 10
    1 / -0.25

    Twelve men can do a job in 8 days. Six days after they start, 4 men join them. How many more days will it take to do the job?

    Solution

    Total work = 12 × 8 = 96.

    12 men finish 6 days of work = 12 × 6 = 72.

    ∴ Work left = 96 – 72 = 24.

    Now number of men = 12 + 4 = 16

     

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