Electrical and ...

A single-phase energy meter is tested for half an hour run at a supply voltage of 230 V and a load current of 10 A at a 0.8 lag power factor. The dial reading at the start was 57.35 and at the end of the test was 58.25. The error in meter registration in kWh is _______ (up to two decimal places)

The brake magnet of an error free electromechanical induction type energy meter is shifted from its position and moved a small distance towards the edge of the disc. Then the meter will

An energy meter having a meter constant of 2400 rev per KWH is found to make 10 revolutions in 90S. The load power is --- (in W)

A single phase 240 V, 20 A, induction type watt hour meter is working correctly when tested at half load rated voltage and unity power factor for 1 minute, the disc rotates at 32 rpm. The meter constant of the meter is _____________ (in rev/kWh)

An energy meter is designed to make 120 revolutions of disc for one unit of energy. if it connected to load carrying 50 A at 220 V and 0.5 power factor for an hour. If it actually makes 600 revolutions, find the percentage error.

A single phase watt meter is operating on 240 V drawing 12 A. The meter revolves for 8 hours and makes 2400 revolutions. If meter constant is 400 revolutions / kWh, What is the power factor of the load?

An energy meter is designed to have 80 revolutions of the disc for per unit of energy consumption. The load is carrying 30 A at 230 V and 0.6 power factor. Find the percentage error if the meter makes 340 revolutions.

A domestic load consists of 10 lamps of 100 W each, three fans of 60 W each and two heaters of 1 kW each, all the loads operating for 1 hour. Energy consumed is measured using an energy-meter having a constant of 1500 revolutions per kWh. The number of revolutions recorded by the meter is 4500. The percentage error in the energy-meter reading is:

A correctly adjusted single phase 240 V induction watt-hour meter has a meter constant of 600. revolutions per kWh. Determine the speed of the disc, for a current of 10 A at a power factor of 0.8 lagging. If the lag adjustment is altered so that the phase angle between voltage coil flux and the applied voltage is 86°. Calculate the error introduced at 0.5 of lagging.