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Electrochemistry Test - 18

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Electrochemistry Test - 18
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  • Question 1
    4 / -1
    Given below are the half- cell reactions
    Mn2+ + 2e → Mn; Eo = ‒ 1.18e V
    2(Mn3+ + e → Mn2+) Eo = + 1.51e V
    The Eo for 3 Mn2+ → Mn + 2Mn3+ will be
    Solution

  • Question 2
    4 / -1
    What is the cell potential (standard emf, E°) for the reaction below ?
    [E°(Fe2/(aq)Fe) = 0.44 V and E°(O2(g)/H2O/OH ) = + 0.4V]
    2Fe (s) + O2 (g) + 2H2O (l) ⇌ 2Fe2+ (aq) + 4OH (aq)
    Solution

  • Question 3
    4 / -1

    Solution

  • Question 4
    4 / -1
    Zinc is used to reduce iron because
  • Question 5
    4 / -1

  • Question 6
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    Solution

  • Question 7
    4 / -1

  • Question 8
    4 / -1
    Aluminium displaces hydrogen from acids but copper does not. A galvanic cell prepared by combining Cu / Cu2+ and Al/ Al3+ has an emf of 2.0 V at 298 K. If the potential of copper electrode is +0.34 V, that of aluminimum electrode is
    Solution

  • Question 9
    4 / -1
    The standard emf. of a cell Zn/Zn2+|| Fe2+/Fe, if electrode potentials for (Zn/Zn2+) and (Fe2+/Fe) are 0.763 V and - 0.44 V respectively is
  • Question 10
    4 / -1
    The electrochemical cell shown below is a concentration cell. M / M2+ (saturated solution of a sparingly soluble salt, MX2) 11M2+ (0.00001 mol dm-3/ M) . The emf of the cell depends on the difference in concentration of M2+ ions at the two electrodes. The emf of the cell at 298 is 0.059 V. The value of ∆G (kJ mol-1 ) for the given cell is (take 1F = 96500C mol-1 )
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