Organic Chemistry Test

Result

Organic Chemistry Test - 43

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Weekly Quiz Competition

Question 1
4 / -1

The enolic form of acetone contains

A
Nine σ − bonds, one bond π − bonds and two lone pairs

B
Eight σ − bonds,two bonds π − bonds and two lone pairs

C
Nine σ − bonds,one π − bond andlone pair

D
Nine σ – bonds, two π – bonds and one lone pair

Solution
Question 2
4 / -1

The hybridization of carbon atoms in C-C single bond of HC ≡ C — C H = CH₂ is

A
sp³ - sp³

B
sp² - sp³

C
sp - sp²

D
sp³ - sp

Solution
Question 3
4 / -1

A straight chain hydrocarbon has the molecular formula C8H10. The hybridization of the carbon atoms from one end of the chain to the other are respectively sp³, sp², sp², sp³, sp², sp² and sp.
The structural formula of the hydrocarbon would be :

A
CH₃C ≡ CCH₂ — CH = CHCH = CH₂

B
CH₃CH₂ — CH = CHCH = CHC ≡ CH

C
CH₃CH = CHCH₂ — C ≡ CCH = CH₂

D
CH₃CH = CHCH₂ — CH = CHC ≡ CH

Solution
Question 4
4 / -1

Homolytic fission of C—C bond in ethane gives an intermediate in which carbon is

A
sp³ - hybridised

B
sp² - hybridised

C
sp - hybridised

D
sp²d - hybridised
Question 5
4 / -1

Which is the correct symbol relating the two Kekule structures of benzene?

A

B

C
≡

D
Question 6
4 / -1

When the hybridization state of carbon atom changes from sp³ to sp² and finally to sp, the angle between the hybridized orbitals

A
decreases gradually

B
decreases considerably

C
is not affected

D
increases progressively
Question 7
4 / -1

The kind of delocalization involving sigma bond orbitals is called

A
Inductive effect

B
Hyperconjugation effect

C
Electromeric effect

D
Mesomeric effect
Question 8
4 / -1

A
(i) and (v)

B
(ii) and (iii)

C
(ii), (iii) and (iv

D
(iv)
Question 9
4 / -1

Which of the following will show aromatic behaviour ?

A

B

C

D

Solution
Question 10
4 / -1

The bond length between sp³ - hybridized carbon and other carbon atom is minimum in

A
Propane

B
Propyne

C
Propene

D
Butane

Solution