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Solution Test - 4

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Weekly Quiz Competition
  • Question 1
    1 / -0

    When KCI crystal is heated into the vapour of potassium which of the following is not the correct observation?

    Solution

    The crystal is paramagnetic due to the presence of unpaired electrons in the anion sites.

  • Question 2
    1 / -0

    Lead zirconate (PbZrO3) crystal has its electric dipoles………and is called……………

    Solution

    Lead zirconate (PbZrO3) crystal has its electric dipoles Aligned in alternate directions and is called anti-ferroelectric.

     

  • Question 3
    1 / -0

    When soap or detergent is added to water

    Solution

    When soap or detergent is added to water Surface tension decreases.

  • Question 4
    1 / -0

    Surface energy of a liquid is

    Solution

    Surface energy of a liquid is the work done to increase the surface area by unity.

  • Question 5
    1 / -0

    The S.I. Units of surface tension and viscosity are respectively

    Solution

    S.I. Units of surface tension Nm−1,and viscosity Nm−2s.

  • Question 6
    1 / -0

    A liquid usually supercools (fall of temperature below its freezing point without freezing) when cooled rapidly. However after some supercooling, temperature rises suddenly to the freezing point despite the cooling. nd the source of heat that causes the temperature to rise.

    Solution

    When super cooled liquid starts freezing, latent of freezing (- latent heat of fusion of the solid) is evolved.

     

  • Question 7
    1 / -0

    In benzene the intermolecular forces are:

    Solution

    In benzene the intermolecular forces are dispersion forces.

  • Question 8
    1 / -0

    A mineral having the formula AB2 crystallizes in ccp lattice with A atoms occupying the lattice points. Pick out the correct statements of the following

    Solution

    Number of A cations per unit cell =4

    Number of B anions per unit cell must be = 2 ×4=8

    Number of tetrahedral voids per unit cell = 2 × 4 = 8

    Number of octahedral voids per unit all = 1 × 4 = 4.

    Hence, occupancy of tetrahedral voids = 100%

     

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