Nomenclature & Isomerism Test

Result

Nomenclature & Isomerism Test - 2

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following statement is true regarding aspirin, a commonly used antipyretic and analgesic? Given pK_a for aspirin = 3.5; pH in stomach and small intestine is 2.5 and 8 respectively

A
It is ionized neither in stomach nor in intestine

B
It is ionized in the stomach and almost unionized in the small intestine

C
It is ionized in the small intestine and almost unionized in the stomach.

D
It is completely ionized in the stomach and almost unionized in the small intestine

Solution

pK_a value (3 .5) for aspirin indicates that it should be ionizable in basic medium (pH 8) and unionizable in acidic medium (pH 2.5)
Question 2
1 / -0

Which of the following statement is/are true regarding the following chemical reaction?

CH₃CHO → CH₃CHOHCN

A
The product is a mixture of two compounds which can be separated by fractional distillation

B
Two of the above three statements are false

C
The product on hydrolysis gives a mixture of two compounds:

D
The product is a mixture of two compounds which can’t be separated by fractional distillation

Solution

Since the product, CH₃CHOHCN has a chiral carbon and is a mixture of two enantiomers (racemic mixture) which can't be separated by fractional distillation.
Question 3
1 / -0

Statement-1: Rearrangement of a carbocation due to alkyl shift is an example of Lewis acid basereaction.

Statement-2: Carbocation is an electrophile and can accept lone pair of electrons from alkyl group.

A
Both Statement-1 and Statement-2 are true and Statement-2 is the correct explanation of Statement-1

B
Both Statement-1 and Statement-2 are true and Statement-2 is not the correct explanation of Statement-1

C
Statement-1 is true but Statement-2 is false

D
Statement-1 is false but Statement-2 is true

Solution

Statement - 2 is the correct explanation of statement-1.
Question 4
1 / -0

Which statement is true regarding hybrid orbital number rule (HON rule)?

A
Every unshared pair of electrons on an atom is present in an HO.

B
An unpaired electron is not present is HO

C
Every or bond is formed by the use of a hybrid orbital

D
All are true

Solution

HON rule is valid for second period elements and with few exceptions for elements in higher periods.