Structure of Atom Test

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Structure of Atom Test - 5

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Weekly Quiz Competition

Question 1
4 / -1

If ionization potential for hydrogen atom is 13.6 eV, then ionization potential for He⁺ will be

A
54.4 eV

B
6.8 eV

C
13.6 eV

D
24.5 eV

Solution
Question 2
4 / -1

Non-directional orbital is

A
4p

B
4d

C
4f

D
3s
Question 3
4 / -1

In a multi-electron atom, which of the following orbitals described by the three quantum numbers will have the same energy in the absence of magnetic and electric fields ?
I . n = 1, l = 0, m = 0
II. n = 2, l = 0, m = 0
III. n = 2, l = 1, m = 1
IV n = 3, l = 2, m = 1
V. n = 3, l = 2, m = 0

A
IV and V

B
III and IV

C
II and III

D
I and II
Question 4
4 / -1

Which of the following statements in relation to the hydrogen atom is correct ?

A
3s, 3p and 3d-orbitals all have the same energy

B
3s and 3p-orbitals are of lower energy than 3d-orbital

C
3p-orbital is lower in energy than 3d-orbital

D
3s-orbital is lower in energy than 3p-orbital
Question 5
4 / -1

Which of the following is non-permissible ?

A
n = 4, l = 3, m = 0

B
n = 4, l = 2, m = 1

C
n = 4, l = 4, m = 1

D
n = 4, l = 0, m = 0
Question 6
4 / -1

The electronic configuration of Cu is

A
[Ne] 3s², 3p⁶, 3d⁹, 4²

B
[Ne] 3s², 3p⁶, 3d¹⁰, 4s¹

C
[Ne]3s², 3p⁶, 3d³, 4s², 4p⁶

D
[Ne]3s², 3p⁶, 3d⁵, 4s², 4p⁴

Solution
Question 7
4 / -1

The electrons identified by quantum numbers n and l
I. n = 4, l = 1
II. n = 4, l = 0
III. n = 3, l = 3
IV . n = 3, l = 1
can be placed in order of increasing energy as

A
(3) < (4) < (2) < (1)

B
(4) < (2) < (3) < (1)

C
(2) < (4) < (1) < (3)

D
(1) < (3) < (2) < (4)
Question 8
4 / -1

For the valency electron in copper, the four quantum numbers are

A
n = 4, l = 0, m = 0, s = 1/ 2

B
n = 4, l = 0, m = + 2, s = 1/ 2

C
n = 4, l = 1, m = +2, s = 1/ 2

D
n = 4, l = 1, m = 0, s = 1/ 2

Solution
Question 9
4 / -1

Which of the following laws will represent the pairing of electron in a subshell after each orbital is filled with one electron ?

A
Pauli's exclusion principle

B
Hund's rule

C
Heisenberg's uncertainty principle

D
Hess law
Question 10
4 / -1

The representation of the ground state electronic configuration of He by box - diagram as ↑↑ is wrong because it violates

A
Heisenberg's uncertainty principle

B
Bohr's quantization theory of angular momenta

C
Pauli exclusion principle

D
Hund's rule

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Re-Attempt Weekly Quiz Competition

Structure of Atom Test - 5

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Structure of Atom Test - 5

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Question 1

54.4 eV

6.8 eV

13.6 eV

24.5 eV

Solution

Question 2

4p

4d

4f

3s

Question 3

IV and V

III and IV

II and III

I and II

Question 4

3s, 3p and 3d-orbitals all have the same energy

3s and 3p-orbitals are of lower energy than 3d-orbital

3p-orbital is lower in energy than 3d-orbital

3s-orbital is lower in energy than 3p-orbital

Question 5

n = 4, l = 3, m = 0

n = 4, l = 2, m = 1

n = 4, l = 4, m = 1

n = 4, l = 0, m = 0

Question 6

[Ne] 3s2, 3p6, 3d9, 42

[Ne] 3s2, 3p6, 3d10, 4s1

[Ne]3s2, 3p6, 3d3, 4s2, 4p6

[Ne]3s2, 3p6, 3d5, 4s2, 4p4

Solution

Question 7

(3) < (4) < (2) < (1)

(4) < (2) < (3) < (1)

(2) < (4) < (1) < (3)

(1) < (3) < (2) < (4)

Question 8

n = 4, l = 0, m = 0, s = 1/ 2

n = 4, l = 0, m = + 2, s = 1/ 2

n = 4, l = 1, m = +2, s = 1/ 2

n = 4, l = 1, m = 0, s = 1/ 2

Solution

Question 9

Pauli's exclusion principle

Hund's rule

Heisenberg's uncertainty principle

Hess law

Question 10

Heisenberg's uncertainty principle

Bohr's quantization theory of angular momenta

Pauli exclusion principle

Hund's rule

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[Ne] 3s², 3p⁶, 3d⁹, 4²

[Ne] 3s², 3p⁶, 3d¹⁰, 4s¹

[Ne]3s², 3p⁶, 3d³, 4s², 4p⁶

[Ne]3s², 3p⁶, 3d⁵, 4s², 4p⁴