Chemistry Test 114

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Chemistry Test 114

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Weekly Quiz Competition

Question 1

4 / -1

Match the Column: (For molecular geometry)

	Column-I		Column-II
(a)	SF₄	(P)	Tetrahedral
(b)	BrF₃	(Q)	Pyramidal
(c)	BrO₃^–	(R)	See-saw
(d)	NH₄⁺	(S)	T-shape (Bent T)

a–P, b–Q, c–R, d–S

a–S, b–R, c–P, d–Q

a–R, b–S, c–Q, d–P

a–Q, b–S, c–R, d–P

Question 2
4 / -1

Select the not incorrect for dipole moment order ?

A
NH₃ > NCl₃

B
XeF₂ = XeF₄ < SO₂

C
P(CH₃)₂ (CF₃)₃ < P (CF₃)₂(CH₃)₃

D
A & B both are correct

Solution
Question 3
4 / -1

Which of the following option is/are incorrect

A
IE₁ of Be > IE₁ of Be^–

B
IE₁ of Be^– > IE₁ of Be

C
|IE₁ of Be^–| = |EA of Be|

D
IE₁ of Be > IE₁ of B
Question 4
4 / -1

Which of the following set of quantum numbers represent the highest energy of an atom :-

A
n = 3,   ℓ = 1,   m = 1,   s = + 1/2

B
n = 3,   ℓ = 2,   m = 1,   s = + 1/2

C
n = 4,   ℓ = 0,   m = 0,   s = + 1/2

D
n = 3,   ℓ = 0,   m = 0,   s = + 1/2
Question 5
4 / -1

The group of metals commonly found in the form of sulphide ore-

A
Al, Fe, Pb

B
Ag, Al, Pb

C
Ag, Pb, Cu

D
Pb, Al, Na

Solution

Ag, Al, Pb, Cu are isolated from sulphide ores.
Question 6
4 / -1

The theoretical magnetic moment of cobalt (Co) after removing three electrons is

A
3.87 BM

B
4.90 BM

C
1.73 BM

D
2.84 BM

Solution
Question 7
4 / -1

The total number of optically active isomers of [Co(en)₂Cl₂]Cl -

A
2

B
3

C
4

D
5

Solution

Minimum oxidation of Cu = +1
Question 8
4 / -1

The structure of compound:

A
(1)

B
(2)

C
(3)

D
(4)

Solution
Question 9
4 / -1

The product E would be :

A
(1)

B
(2)

C
(3)

D
(4)

Solution

Question 10

4 / -1

Match the items given in Column-I with that given in Column-II.

	Column-I		Column-II
(A)	Nucleotide	(p)	Linkage in carbohydrates
(B)	Peptide linkage	(q)	Linkage in proteins
(C)	Glycoside linkage	(r)	A sugar and heterocyclic base combination
(D)	Nucleoside	(s)	The monomeric unit in nucleic acids

A → s; B → q; C → p; D → r

A → q; B → p; C → s; D → r

A → p; B → s; C → r; D → q

A → s; B → r; C → q; D → p

Solution

Theory based

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Chemistry Test 114

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Chemistry Test 114

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Question 1

a–P, b–Q, c–R, d–S

a–S, b–R, c–P, d–Q

a–R, b–S, c–Q, d–P

a–Q, b–S, c–R, d–P

Question 2

NH3 > NCl3

XeF2 = XeF4 < SO2

P(CH3)2 (CF3)3 < P (CF3)2(CH3)3

A & B both are correct

Solution

Question 3

IE1 of Be > IE1 of Be–

IE1 of Be– > IE1 of Be

|IE1 of Be–| = |EA of Be|

IE1 of Be > IE1 of B

Question 4

n = 3, ℓ = 1, m = 1, s = + 1/2

n = 3, ℓ = 2, m = 1, s = + 1/2

n = 4, ℓ = 0, m = 0, s = + 1/2

n = 3, ℓ = 0, m = 0, s = + 1/2

Question 5

Al, Fe, Pb

Ag, Al, Pb

Ag, Pb, Cu

Pb, Al, Na

Solution

Question 6

3.87 BM

4.90 BM

1.73 BM

2.84 BM

Solution

Question 7

2

3

4

5

Solution

Question 8

(1)

(2)

(3)

(4)

Solution

Question 9

(1)

(2)

(3)

(4)

Solution

Question 10

A → s; B → q; C → p; D → r

A → q; B → p; C → s; D → r

A → p; B → s; C → r; D → q

A → s; B → r; C → q; D → p

Solution

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NH₃ > NCl₃

XeF₂ = XeF₄ < SO₂

P(CH₃)₂ (CF₃)₃ < P (CF₃)₂(CH₃)₃

IE₁ of Be > IE₁ of Be^–

IE₁ of Be^– > IE₁ of Be

|IE₁ of Be^–| = |EA of Be|

IE₁ of Be > IE₁ of B