Chemistry Test 293

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Chemistry Test 293

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Weekly Quiz Competition

Question 1
4 / -1

In the complex ion , the oxidation state of copper and its coordination number are respectively:

A
+2, 4

B
+1, 4

C
+2, 2

D
+1, 2
Solution
- The ammonia (NH₃) molecules are neutral ligands, so the overall charge on the complex ion (+2) is solely due to the copper ion. Thus, copper has an oxidation state of +2.
- The coordination number is the number of ligands attached, which is 4.
Question 2
4 / -1

How many distinct monochloro structural isomers are formed in the free radical chlorination of (CH₃)₂CHCH₂CH₃ ?

A
2

B
3

C
4

D
5

Solution
Question 3
4 / -1

Which of the following sequences correctly represents the reaction of a carboxylic acid with ammonia to form an amide?

A
RCOOH → RCOCl → RCONH₂

B
RCOOH → RCOOR′ → RCONH₂

C
RCOOH → RCOONH₄→ RCONH₂

D
RCOOH → RNH₂→ RCONH₂

Solution

Step 1: Carboxylic acids first react with ammonia to form ammonium salts (RCOONH₄).

Step 2: Upon heating, these salts dehydrate to yield amides (RCONH₂).
Question 4
4 / -1

Methyl tert-butyl ether on heating with HI of one molar concentration gives

A
CH₃I + (CH₃)₃COH

B
CH₃OH + (CH₃)₃CI

C
CH₃I + (CH₃)₃CI

D
None of the above

Solution
Question 5
4 / -1

Unpleasant smelling carbylamines are formed by heating alkali and chloroform with

A
Any amine

B
Any aliphatic amine

C
Any aromatic amine

D
Any primary amine

Solution
Question 6
4 / -1

The rate of a first order reaction is 1.5 × 10⁻² molL⁻¹ min⁻¹ at 0.5 M concentration of the reactant. The half life of the reaction is

A
8.73 min

B
7.53 min

C
0.383 min

D
23.1 min

Solution
Question 7
4 / -1

Aniline and methyl amine can be differentiated by

A
Reaction with chloroform and aqueous solution of KOH

B
Diazotisation followed by coupling with phenol

C
Reaction with HNO₂

D
None of these

Solution
Question 8
4 / -1

The half-life of a reaction is inversely proportional to the square of the initial concentration of the reactant. Then the order of the reaction is

A
0

B
1

C
2

D
3

Solution
Question 9
4 / -1

If a substance with half life 3 days is taken at other place. In 12 days what amount of substance is left now

A
1/4

B
1/8

C
1/16

D
1/32

Solution
Question 10
4 / -1

The main reason for larger number of oxidation state exhibited by the actinides than that corresponding lanthanides, is

A
lesser energy difference between 5 f and 6d orbitals than between 4 f and 5d-orbitals

B
larger atomic size of actinides than the lanthanides

C
more energy difference between 5 f and 6d orbitals than between 4 f and 5d-orbitals

D
greater reactive nature of the actinides than the lanthanides.

Solution