JEE Advanced Mix Test 45

Result

JEE Advanced Mix Test 45

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
4 / -1

A block of mass √3/10 kg is placed on a rough horizontal surface as shown in the figure.

A force of 1 N is applied at one end of the block, and the block remains stationary. The normal force exerted by the surface on block acts through (g = 10 m/s²)

A
the centre of mass of block

B
point A

C
the point at a distance 2 cm from A

D
the point at a distance 5 cm from A

Solution
Question 2
4 / -1

Three resistances each of 4 Ω are connected to form a triangle. The resistance between any two terminals is

A
12 Ω

B
2 Ω

C
6 Ω

D
8/3 Ω

Solution

The two resistance are connected in series and the resultant is connected in parallel with the third resistance.
Question 3
4 / -1

A ray of light is incident on the interface between water and glass at an angle i and refracted parallel at the water surface, then value of μ_g will be

A

B

C
4/3

D
1

Solution
Question 4
4 / -1

A
CH₃CH₂Br and HCHO

B

C
CH₃Br and CH₃CH₂CHO

D
CH₃Br and CH₃CHO

Solution
Question 5
4 / -1

Directions For Questions

Directions: The following question is based on the paragraph given below.

P and Q are isomers of dicarboxylic acid C₄H₄O₄. Both decolorise Br₂/H₂O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.

...view full instructions

The compounds formed from P and Q respectively are:

A
Optically active S and optically active pair (T, U)

B
Optically inactive S and optically active pair (T, U)

C
Optically active pair (T, U) and optically active S

D
ptically inactive pair (T, U) and optically inactive S

Solution

Since both the dioic acids decolourise Br₂/H₂O, these are unsaturated dioic acids and display geometrical isomerism.

And also, 'P' forms a cyclic anhydride; therefore, it is a cis isomer.

'P' is maleic acid and 'Q' is fumaric acid.

On treatment with KMnO₄ solution, both 'P' and 'Q' form tartaric acid which exists as three stereoisomers: S, T and U.

Maleic acid 'P' yields the meso isomer 'S', which is optically inactive.

Fumaric acid 'Q' yields the optically active isomer (T, U).

Hence, option (2) is correct.
Question 6
4 / -1

1 mole of an ideal gas A(C_{v, m} = 3R) and 2 moles of an ideal gas B are (C_v,m = 3/2 R) taken in a container and expanded reversible and adiabatically from 1 liter to 4 liters starting from initial temperature of 320 K. ΔE or ΔU For the process is :

A
−140R

B
−240R

C
−480R

D
−960R

Solution
Question 7
4 / -1

During the process of electrolytic refining of copper, some metals present as impurity settle as 'anode mud'. These are

A
Fe and Ni

B
Ag and Au

C
Pb and Zn

D
Se and Ag

Solution

During electrolysis, noble metals (inert metals) like Ag, Au and Pt are not affected and separate as anode mud from the impure anode
Question 8
4 / -1

f(x), g(x) and h(x) are all continuous and differentiable functions in [a, b], a < c < b and f(a) = g(a) = h(a). Point of intersection of the tangent at x = c with chord joining x = a and x = b is on the left of c in y = f(x), on the right in y = h(x) and tangent at x = c is parallel to the chord in the case of y = g(x).

If f’(x) > g’(x) > h’(x)

A
f(b) < g(b) < h(b)

B
f(b) > g(b) > h(b)

C
f(b) ≤ g(b) ≤ h(b)

D
f(b) ≥ g(b) ≥ f(b)

Solution
Question 9
4 / -1

A point P moves such that the tangents PT₁ and PT₂ from it to the hyperbola 4x²− 9y² = 36 are mutually perpendicular. Then the equation of the locus of P is

A
x²+ y²= 5

B
x⁴− y⁴= 4

C
x⁵+ y⁵= 2

D
x¹− y¹=4

Solution
Question 10
4 / -1

The tangent at any point P(a secθ, b tanθ) of the hyperbola makes an intercept of length p between the point of contact and the transverse axis of the hyperbola. If p₁, p₂ are the lengths of the perpendiculars drawn from the foci on the normal at P, then

A
p is an arithmetic mean between p₁ and p₂

B
p is a geometric mean between p₁ and p₂

C
p is a harmonic mean between p₁ and p₂

D
none of these

Solution