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JEE Advanced Mix Test 70

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JEE Advanced Mix Test 70
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  • Question 1
    4 / -1

    An engine whistling at a constant frequency n0 and moving with a constant velocity goes past a stationary observer. As the engine crosses him, the frequency of the sound heard by him changes by a factor f. The actual difference in the frequency of the sound heard by him before and after the engine across him is

    Solution

     

  • Question 2
    4 / -1

    A ball of density ρ0 falls from rest from point P onto the surface of a liquid of density ρ in time T. It enters the liquid stops moves up and returns to P in a total time 3T. Neglect viscosity, surface tension and splashing. The ratio p/p0 is equal to

    Solution

     

  • Question 3
    4 / -1

    When an object is placed in front of a concave mirror of focal length f, a virtual image is produced with a magnification of 2. To obtain a real image with a magnification of 2. The object has to be moved by a distance equal to

    Solution

    Calculate the initial and final distance of object from the concave mirror.

     

  • Question 4
    4 / -1

    Sulphur reacts with chlorine in 1 : 2 ratio and forms X. Hydrolysis of X gives a sulphur compoundY. What is the hybridization state of central atom in the compound Y?

    Solution

     

  • Question 5
    4 / -1

    Find out the correct representation of trans - decaline

    Solution

     

  • Question 6
    4 / -1

    50 ml of a solution containing 10-3 mol of Ag+ is mixed with 50 ml of a 0.1 M HCl solution. Howmuch [Ag+] remains in solution? Given: Ksp of AgCl = 10-10

    Solution

     

  • Question 7
    4 / -1

    If the equation x4 – 4x3 + ax2 + bx + 1 = 0 has four positive roots then

    Solution

     

  • Question 8
    4 / -1

    Find the point p on the line 2x + 3y + = 0 such that |PA - PB| is maximum where A is (2,0) and B is (0,2)

    Solution

     

  • Question 9
    4 / -1

    Find the coefficient of x5 in the expansion of (2 – x + 3x2)6

    Solution

     

  • Question 10
    4 / -1

    If tan3θ + tanθ = 2tan2θ then θ is equal to (n ∈ z)

    Solution

    θ = nπ,n ∈ z or 2θ = nπ ∵  θ = nπ/2  is not for possible as n is odd tanθ is not define.

    Hence θ = nπ, n ∈ z is the only solution.

     

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