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Mathematics Test 210

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Mathematics Test 210
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  • Question 1
    4 / -1

    Solution

     

  • Question 2
    4 / -1

    At an election, a voter may vote for any number of candidates not greater than the number to be elected. There are 10 candidates and 4 are to be elected. If a voter votes for at least one candidate, then the number of ways in which he can vote, is

    Solution

    Total number of ways

    10C1 + 10C2 + 10C3 + 10C4

    = 10 + 45 + 120 + 210 = 385

     

  • Question 3
    4 / -1

    If 2y - a is the harmonic mean between y − x and y − z , then x - a, y - a and z - a are in

    Solution

    It is given that, y − x, 2(y − a) and (y − z)y - x, 2y - a and y - z are in harmonic progression.

     

  • Question 4
    4 / -1

     are probabilities of mutually exclusive events of a random experiment, then the range of p is

    Solution

     

  • Question 5
    4 / -1

    The equation of the bisectors of the angles between the lines represented by the equation 2(x + 2)2 + 3(x + 2)(y - 2) -2(y - 2)2 = 0 is

    Solution

    2(x + 2)2 + 3(x + 2)(y - 2) -2(y - 2)2 = 0

    Assume x + 2 = X, y − 2 = Y

    2X2 + 3XY − 2Y2 = 0

    Equation of the bisectors would be

     

  • Question 6
    4 / -1

    The possible values of scalar kk such that the matrix A−1− kI is singular, where 

    Solution

     

  • Question 7
    4 / -1

    If 1 + sinθ + sin2θ + sin3θ +.....=4 + 2√3, 0 < θ < π, then

    Solution

     

  • Question 8
    4 / -1

    If f(x) = 3x4 + 4x3 − 12x2 + 12 the f(x) is

    Solution

    Since, f(x) = 3x4 + 4x3 − 12x2 + 12

    f′(x) = 12x3 + 12x2 − 24x

    = 12x(x − 1)(x + 2)

    From the above expression it is clear that f(x) is increasing in (−2, 0)∪(1, ∞) and decreasing in (−∞, −2)∪(0, 1)

     

  • Question 9
    4 / -1

    A man whose eye level is 1.5 meter above the ground observes the angle of elevation of a tower to be 60°. If the distance of the man from the tower is 10 meter, the height of the tower is

    Solution

     

  • Question 10
    4 / -1

    The area bounded by the curve y = x/ 2 , x-axis and x = 2 is

    Solution

     

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