Mathematics Test 252

Result

Mathematics Test 252

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Weekly Quiz Competition

Question 1
4 / -1

A
a negative integer

B
an irrational number

C
a rational number

D
none of these

Solution
Question 2
4 / -1

The mid points of the sides of a triangle are (5, 0), (5, 12) and (0, 12), then orthocentre of this triangle is

A
(0, 0)

B
(0, 24)

C
(10, 0)

D

Solution
Question 3
4 / -1

If k + |k + z²| = |z|² where k is real, then a possible argument of z is

A
0

B
π

C
π/2

D
none of these

Solution
Question 4
4 / -1

If 2 sec 2α = tan β + cot β, then one of the values of α + β is

A
π

B

C
π/4

D
π/2

Solution
Question 5
4 / -1

The axis of a parabola lie along the line y = x and the distance of its vertex from origin is √2 and that of focus is 2√2. If both focus and vertex lie in the first quadrant, then the equation of the parabola will be

A
(x + y)²= (x − y − 2)

B
(x − y)²= (x + y − 2)

C
(x − y)²= 4(x + y − 2)

D
(x − y)²= 8(x + y − 2)

Solution
Question 6
4 / -1

A
√3

B
1/√3

C

D
None of these

Solution
Question 7
4 / -1

If sin(xy) + cos(xy) = 1 and tan(xy) ≠ 1, then dy/dx is equal to

A
-y/x

B

C
−xy

D
xy

Solution
Question 8
4 / -1

The solution of xdx + ydy = x²ydy − xy²dx is

A
x²− 1 = C(1 + y²)

B
x²+ 1 = C(1 − y²)

C
x²− 1 = C(1 − y²)

D
x²+ 1 = C(1 + y²)

Solution
Question 9
4 / -1

If the tangents drawn to the hyperbola 4y² = x² + 1 intersect the co-ordinate axes at distinct points A and B, then the locus of the midpoint of AB is

A
4x² - y² + 16x²y² = 0

B
x² - 4y² + 16x²y² = 0

C
x² - 4y² - 16x²y² = 0

D
4x² - y² - 16x²y² = 0

Solution
Question 10
4 / -1

If the function f defined as is continuous at x = 0, then the ordered pair (k, f(0)) is equal to

A
(2, 1)

B
(3, 1)

C
(3, 2)

D
(1/3, 2)

Solution