Self Studies

Mathematics Test 300

Result Self Studies

Mathematics Test 300
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies
Weekly Quiz Competition
  • Question 1
    4 / -1

    Solution

     

  • Question 2
    4 / -1

    A stone thrown vertically upward satisfied the equation s = 64t - 16t2, where s is in metre and t is in second. What is the time required to reach the maximum height by the stone?

    Solution

    Given, s = 64t - 16t2,

    So, the function s(t) is maximum when, 

    s'(t) = 0 and s"(t) < 0

    ⇒ s'(t) = 64 - 16(2t) = 0 

    ⇒ 64 = 32 t 

    ⇒ t = 2

    And at t = 2, s"(t) = -32 < 0

    So, s(t) is maximum at t = 2.

    So, The time required to reach the maximum height by the stone is 2s.

    ∴ The correct answer is an option (2).

     

  • Question 3
    4 / -1

    The area (in sq. units) of the smaller region lying above the X-axis and bounded between the circle x2 + y2 = 2ax and the parabola y2 = ax is

    Solution

     

  • Question 4
    4 / -1

    Solution

     

  • Question 5
    4 / -1

    Solution

    Given,

    Expression = cot⁻¹ [ (√(1−sin x) + √(1+sin x)) / (√(1−sin x) − √(1+sin x)) ]

    Let A = (√(1−sin x) + √(1+sin x)) / (√(1−sin x) − √(1+sin x))

    Multiply numerator and denominator by conjugate of denominator:

    ⇒ A = [(√(1−sin x) + √(1+sin x))²] / [(1−sin x) − (1+sin x)]

    ⇒ A = [1−sin x + 1+sin x + 2√((1−sin x)(1+sin x))] / [−2sin x]

    ⇒ A = [2 + 2√(1−sin²x)] / (−2sin x)

    ⇒ A = [2 + 2cos x] / (−2sin x)

    ⇒ A = −(1 + cos x) / sin x

    ⇒ A = −cot(x/2) [Using identity: cot(x/2) = (1 + cos x) / sin x]

    ⇒ cot⁻¹(A) = cot⁻¹(−cot(x/2))

    ⇒ cot⁻¹(cot(π − x/2)) = π − x/2

    ∴ Required value is π − x/2

     

  • Question 6
    4 / -1

    If y(x) is a solution of the differential equation 

    Solution

    The differential equation is:

    Hence, the correct answer is Option (c).

     

  • Question 7
    4 / -1

    Let the point P of the focal chord PQ of the parabola y2 =16x be (1,−4). If the focus of the parabola divides the chord PQ in the ratio m:n, gcd (m,n) = 1,. Then m2 + n2 is equal to

    Solution

     

  • Question 8
    4 / -1

    Let the area of the triangle formed by a straight line L : x + by + c = 0 with co-ordinate axes be 48 square units. If the perpendicular drawn from the origin to the line L makes an angle of 45∘ with the positive x-axis, then the value of b2 + c2 is

    Solution

     

  • Question 9
    4 / -1

    The centroid of a variable triangle ABC is at the distance of 5 units from the origin. If A = (2,3) and B = (3,2),then the locus of C is

    Solution

     

  • Question 10
    4 / -1

    Solution


     

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now