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    If P(n) = 2 + 4 + 6 + ......... + 2n, n – N then 6 P(m) = m(m + 1) + 2 , 

    ⇒ P(m + 1) = (m + 1) (m + 2) + 2 m – N, so we can conclude that P(n) = n(n+1) + 2 for

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