JEE Main Test 138

Result

JEE Main Test 138

Score
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Rank
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TIME Taken - -

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Weekly Quiz Competition

Question 1
4 / -1

Ten moles of an ideal gas at constant temperature 500 K is compressed from 50 L to 5 L. Work done in the process is (Given, R = 8.31 J – mol ^-1 – K ^-1)

A
–1.2 × 10⁴ J

B
–2.4 × 10⁴ J

C
–4.8 × 10⁴ J

D
–9.6 × 10⁴ J
Question 2
4 / -1

A Carnot engine, having an efficiency of η = 1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

A
99 J

B
90 J

C
1 J

D
100 J

Solution
Question 3
4 / -1

A motor is rotating at a constant angular velocity of 600 rpm. The angular displacement per second is

A

B

C

D

Solution
Question 4
4 / -1

For the given uniform square lamina ABCD, whose centre is O

A

B

C

D

Solution
Question 5
4 / -1

The species having bond order different from that in CO is

A
NO^-

B
NO⁺

C
CN^-

D
N₂

Solution
Question 6
4 / -1

If P, Q and R are angles of ΔPQR, then the value of

A
– 1

B
0

C
1/2

D
1

Solution
Question 7
4 / -1

The shape of XeO₂ F₂ molecule is

A
trigonal bipyramidal

B
square planar

C
tetrahedral

D
see-saw

Solution

The shape of X_eO₂F₂ molecule is see-law shape. Bacause, after drawing the Lewis structure and determining the best one based on formal charges, the xenon atom is left with one lone pair, two double bonds to the oxygen atoms and two single bonds to the fluorine atoms. This is a total of 5 electron domains and 4 different atoms, consist with AX₄E formula of the see-saw molecular geometry.
Question 8
4 / -1

A

B

C

D

Solution
Question 9
4 / -1

A
4 Nm^-1

B
3 Nm^-1

C
2 Nm^-1

D
5 Nm^-1

Solution
Question 10
4 / -1

A

B

C

D

Solution