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JEE Main Test 15

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JEE Main Test 15
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Weekly Quiz Competition
  • Question 1
    4 / -1

    A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

    Solution

    0.50 x 2 = 1.50 x v

    Therefore, v = (2/3) m/s

    Loss of energy = (1/2)(0.5 x 4 - 1.5 x (2/3)2)
    = 0.67 J

  • Question 2
    4 / -1

    Two full turns of the circular scale of a screw gauge cover a distance of 1 mm on its main scale. The total number of divisions on the circular scale is 50. Further, it is found that the screw gauge has a zero error of -0.03 mm. While measuring the diameter of a thin wire, a student notes the main scale reading of 3 mm and the number of circular scale divisions in line with the main scale as 35. The diameter of the wire is

    Solution

    The total reading 
    = 3 mm + 35 × 0.01 = 3.35 mm 
    ∴ the total reading (after correction) 
    = (3.35 + 0.03) mm = 3.38 mm.

  • Question 3
    4 / -1

    Which one of the following conformations of cyclohexane is chiral?

    Solution

    Twisted boat is chiral as it does not have plane of symmetry. 
     

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