Physics Test 202

Result

Physics Test 202

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
4 / -1

The ratio of the energy of an X - ray photon of wavelength 1 Å to that of visible light of wave length 500 Å is

A
1 : 5000

B
5000 : 1

C
1 : 25 x 10⁶

D
25 x 10⁶ : 1
Question 2
4 / -1

The de-Broglie wavelength associated with proton changes by 0.25% if its momentum is changed by P₀. The initial momentum was

A
100 P₀

B
P₀/400

C
401 P₀

D
P₀/100

Solution

Use the formula lamba=h/p you will see that they are inversely related, so if you reduce wavelength by 0.25% then momentum reduces by 1 unit. So that implies Initial momentum is 401Po
Question 3
4 / -1

A fixed volume of iron is drawn into a wire of length l. The extension x produced in this wire by a constant force F is proportional to

A
I/l²

B
1/l

C
l²

D
l

Solution
Question 4
4 / -1

Condensers of capacities 2 μ F and 3 μ F are connected in series and a condenser of capacity 1 μ F is connected in parallel with them. The resultant capacity is

A
0. 5 μ F

B
1.1 μ F

C
22 μ F

D
2. 2 μ F
Question 5
4 / -1

Vapour is injected at a uniform rate in a closed vessel which was initially evacuated. The pressure in the vessel

A
Increases continuously

B
Decreases continuously

C
First increase and then becomes constant

D
First increases and then decreases

Solution
Question 6
4 / -1

What is the coefficient of mutual inductance, when the magnetic flux changes by 2X10^-2 Wb and change in current is 0.01 A ?

A
2 henry

B
3 henry

C
1/2 henry

D
Zero
Question 7
4 / -1

The electric potential V is given as a function of distance x (metre) by V = (5x² + 10x - 9) volt. Value of electric field at x = 1m is

A
-23 V/m

B
11 V/m

C
6 V/m

D
-20 V/m

Solution

V = 5x² + 10x - 9

E = - dv dx

= - (10x + 10)

= -(10 x 1 + 10)

= - 20 V/m
Question 8
4 / -1

If 3.8 x 10^-6 is added to 4.2 x 10^-5 giving due regard to significant figures, then the result will be

A
4.58 x 10^-5

B
4.6 x 10^-5

C
4.5 x 10^-5

D
None of these

Solution
Question 9
4 / -1

The mass and diameter of a planet have twice the value of the corresponding parameters of earth. Acceleration due to gravity on the surface of the planet is

A
9.8 m/sec²

B
4.9 m/sec²

C
980 m/sec²

D
19.6 m/sec²
Question 10
4 / -1

Referring to the above two questions, the acceleration due to gravity is given by

A
10 m/sec²

B
5 m/sec²

C
20 m/sec²

D
2.5 m/sec²

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Physics Test 202

Result

Physics Test 202

Score

-

Rank

-

SHARING IS CARING

Question 1

1 : 5000

5000 : 1

1 : 25 x 106

25 x 106 : 1

Question 2

100 P₀

P₀/400

401 P₀

P₀/100

Solution

Question 3

I/l2

1/l

l2

l

Solution

Question 4

0. 5 μ F

1.1 μ F

22 μ F

2. 2 μ F

Question 5

Increases continuously

Decreases continuously

First increase and then becomes constant

First increases and then decreases

Solution

Question 6

2 henry

3 henry

1/2 henry

Zero

Question 7

-23 V/m

11 V/m

6 V/m

-20 V/m

Solution

Question 8

4.58 x 10-5

4.6 x 10-5

4.5 x 10-5

None of these

Solution

Question 9

9.8 m/sec2

4.9 m/sec2

980 m/sec2

19.6 m/sec2

Question 10

10 m/sec2

5 m/sec2

20 m/sec2

2.5 m/sec2

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.

1 : 25 x 10⁶

25 x 10⁶ : 1

I/l²

l²

4.58 x 10^-5

4.6 x 10^-5

4.5 x 10^-5

9.8 m/sec²

4.9 m/sec²

980 m/sec²

19.6 m/sec²

10 m/sec²

5 m/sec²

20 m/sec²

2.5 m/sec²