Sequences and Series Test

Result

Sequences and Series Test - 7

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Weekly Quiz Competition

Question 1
2 / -0.83

If a ∈R, then the roots of the equation tan x = a are in

A
G.P.

B
H.P.

C
A.P.

D
none of these
Question 2
2 / -0.83

The values of ‘a ’for which the roots of the equation sin x = a in A.P. are

A
- 1 and 1

B
0, 1 and –1

C
0 and 1

D
none of theses
Question 3
2 / -0.83

The sum of first four terms of an A. P. is 56 and sum of last four terms is 112. If the first term is 11, then the number of terms is

A
12

B
10

C
1

D
none of these

Solution
Question 4
2 / -0.83

The ratio of the 7^th to the (n –1)th mean between 1 and 31, when n arithmetic means are inserted between them, is 5 : 9. The value of n is

A
12

B
15

C
13

D
14
Question 5
2 / -0.83

The sum of first n terms of the series 1 –1 + 1 –1 + …is

A
±1

B
(−1)ⁿ

C
- 1

D
1 if n is odd and 0 when n is even
Question 6
2 / -0.83

If a, b, c, d , e are in G. P., then e/c equals

A
d/c

B
c/b

C
d/b

D
b/a
Question 7
2 / -0.83

The product of first n odd terms of a G.P. whose middle term is m is

A
mn

B
n^m

C
mⁿ

D
none of these
Question 8
2 / -0.83

The fourth term of a G. P. is 2, then product of first 7 terms is

A
1/27

B
32

C
128

D
64
Question 9
2 / -0.83

If three positive numbers a, b, c are in G. P. then log a, log b, log c are in

A
H.P.

B
A.G.P.

C
G.P.

D
A.P.
Question 10
2 / -0.83

The nth term of the sequence 5 + 55 + 555 + …. is

A
5/9 (10ⁿ −1)

B
5 ×10^{n −1}

C
5 ×11^{n −1}

D
none of these

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Sequences and Series Test - 7

Result

Sequences and Series Test - 7

Score

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Rank

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SHARING IS CARING

Question 1

G.P.

H.P.

A.P.

none of these

Question 2

- 1 and 1

0, 1 and –1

0 and 1

none of theses

Question 3

12

10

1

none of these

Solution

Question 4

12

15

13

14

Question 5

±1

(−1)n

- 1

1 if n is odd and 0 when n is even

Question 6

d/c

c/b

d/b

b/a

Question 7

mn

nm

mn

none of these

Question 8

1/27

32

128

64

Question 9

H.P.

A.G.P.

G.P.

A.P.

Question 10

5/9 (10n −1)

5 ×10n −1

5 ×11n −1

none of these

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(−1)ⁿ

n^m

mⁿ

5/9 (10ⁿ −1)

5 ×10^{n −1}

5 ×11^{n −1}