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Number System Test - 5

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Number System Test - 5
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  • Question 1
    2 / -0.83

    What is the number if 60% of it added to 60 gives the number itself ?

    Solution

    From ans …150
    40% of numb = 60
    60% of 150 = 90
    90+60 = 150

  • Question 2
    2 / -0.83

    (6084)1/2 = ?

  • Question 3
    2 / -0.83

    9/16 of a number is 51 greater than 50% of the number, then the number is

    Solution

    (9x/16)-(x/2) = 51
    X = 51*16 = 816

  • Question 4
    2 / -0.83

    The sum of the number and its square is 1406. What is the number ?

    Solution

    See the last digit 06 …..go for 7
    Last digit ..37+(37*37) = 7+49 = 16
    So ans: 37

  • Question 5
    2 / -0.83

    The number is 0.01 is how many times as great as the number (0.0001)2  ?

    Solution

    0.01 = 10-2
    (0.0001)2 = 10-8
    10-2 /10-8 = 106

  • Question 6
    2 / -0.83

    In a bag there are coins of 25 paise and 10 paise in the ratio of 5:16. If the bag contains Rs.16 then the number of 10 paise coin is

    Solution

    25*5+10*16 = 285
    Rs 16 = 1600
    No of 10p = 1600*16/285 = 89.82 = 90

  • Question 7
    2 / -0.83

    a+b = c and abc = 30, then what is the value of a3 + b3 –c3 ?

    Solution

    a3 + b3 –c3 = -3(abc) = -3(30) = -90

  • Question 8
    2 / -0.83

    a2 + b2 + c2 = ab + bc + ca then the value of (a+b)/(b+c) is

    Solution

    Equation will be satisfied when a=b=c=1
    (a+b)/c = (1+1)/(1+1) = 2/2 = 1

  • Question 9
    2 / -0.83

    (a-b) = 1, (b-c) = 2 and (c-a) = 3 then the value of (a3 +b3 +c3 -3abc)/(a+b+c) is

    Solution

    a3 + b3 + c3 - 3 a b c =  ( a + b + c ) ( a2 + b2 + c2 - bc - ab - ac )  .
    (a3 +b3 +c3 -3abc)/(a+b+c)
    = 1/2[(a-b) 2 +(b-c)2 +(c-a)2 ]
    = ½(1+4+9)
    = 14/2 = 7

  • Question 10
    2 / -0.83

    If *=+, /=-, + = *, –= / then 43*561+500-100/10 = ?

    Solution

    Given the expression: 43*561+500-100/10

    And the symbol replacements:

    • * becomes  +
    • / becomes  -
    • + becomes  *
    • - becomes  /

    Substituting the symbols, the expression becomes:

    43 + 561 * 500 / 100 - 10

    Now, we solve step-by-step:

    1. 561 * 500 = 280500
    2. 280500 / 100 = 2805

    Now the expression is:

    43 + 2805 - 10

    Continuing with addition and subtraction:

    1. 43 + 2805 = 2848
    2. 2848 - 10 = 2838

    The correct answer is: (d) 2838

  • Question 11
    2 / -0.83

    Two third of a positive number and 25/216 of its reciprocal are equal.The number is

    Solution

    (2/3)x = (25/216)(1/x)
    X2 = (25 ×3)/(216 ×2) = 25/144
    X = 5/12

  • Question 12
    2 / -0.83

    If 2(1/2) is added to a number and the sum multiplied by 4(1/2)and 3 is added to the product and then divide the sum by 1(1/5), the quotient becomes 25 .What is the number ?

    Solution

    {4(1/2)[X+2(1/2)]+3}/[1(1/5)] = 25
    (9X/2)+(45/4)+3 = 25 ×(6/5)
    9X/2 =63/4 X=7/2 or 3(1/2)

  • Question 13
    2 / -0.83

    In a division sum ,the divisor is 3 times the quotient and 6 times the remainder.If the remainder is 2 then the dividend is

    Solution

    Divident = Quotient ×Divisor +Remainder
    Divisor = 6 ×2 = 12
    Q = 12/3 = 4
    Divident = 4 ×12+3 =48+2 = 50

  • Question 14
    2 / -0.83

    The sum of two number is 24.The greatest product of these two numbers can be

    Solution

    X + Y = 24
    Greatest Product then x and y must be equal
    Possibility of getting 24 12+12= 24
    12 ×12 = 144

  • Question 15
    2 / -0.83

    Twenty times a positive integer is less than its square by 96.What is the integer ?

    Solution

    X2 –20X = 96
    X2 -20X-96 = 0
    (X-24)(X+4) = 0
    X= 24, -4
    positive integer = 24

  • Question 16
    2 / -0.83

    If (a-b) 3, (b-c) = 5 and (c-a) = 1 then the value of (a3 +b3 +c3 - 3abc)/(a+b+c)

  • Question 17
    2 / -0.83

    The product of the 2 consecutive odd number is 6723.What is the greater number ?

    Solution

    X ×(X+2) = 6723
    X2 + 2X = 6723
    X2 +2X-6723 = 0
    (X –81)(X+83) = 0
    Greatest number = 83

  • Question 18
    2 / -0.83

    The sum of three number is 264. If the first number be twice the second and third number be one third of the first then the second number is

    Solution

    2X+X+(2X/3) = 264
    (6X+3X+2X)/3 = 264
    11X/3 = 264
    X= (264 ×3)/11 = 72

  • Question 19
    2 / -0.83

    If the number obtained on interchanging the digits of a 2 digit number is 18 more than the original number and the sum of the digit is 8.Then what is the original number?

    Solution

    Unit digit= x ; Ten ’s digit = (8-x)
    [10(8-x)+x] –[10x+(8-x)] = 18
    80-10x+x-10x-8+x = 18
    -18x = 18-80+8
    18x = 54
    X = 54/18 = 3
    8 –x = 8 –3 = 5
    Hence the number is 35

  • Question 20
    2 / -0.83

    The sum of three consecutive multiple of 4 is 72 .What is the largest number ?

    Solution

    4x+(4x+4)+(4x+8) = 72
    12x+12 = 72
    X=(72-12)/12
    X=5
    Largest number = 4(5)+8 = 20+8 = 28

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