Trignometric Ratios, Functions and Equations Test

Result

Trignometric Ratios, Functions and Equations Test - 6

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Weekly Quiz Competition

Question 1
2 / -0.83

What is the value of tan 25 °?

A

B

C
tan 30 °- tan 5 °

D
tan 20 °- tan 5 °

Solution
Question 2
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Find tan 40 °?

A
1/2 tan80⁰

B
1/2 tan60⁰

C

D

Solution
Question 3
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Find the value of 1 + cos2A.

A
-2 sin2A

B
2 sin² A

C
-2 cos2A

D
2 cos² A

Solution

By formula

Cos 2A = Cos ²A-Sin ²A

Cos ²A-Sin ²A=Cos ²A-(1-Cos ²A) =Cos ²A -1 +Cos ²A=2 Cos ²A - 1

so, Cos 2A = 2 Cos ²A - 1
Question 4
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What is the value of cos 4x ?

A
2cos² X

B
sin² 2X –cos² 2X

C
cos² 2X –sin² 2X

D
-2cos² X
Question 5
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What is the value of cos 6X?

A
1 –2sin² 3X

B
2sin² 3X –1

C
cos² 3X –1

D
1 –2cos² 3X
Question 6
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3 Sin 10 °–4 Sin³ 10 °= ?

A
1

B
2

C
-1

D
1/2

Solution

3sinA-4sin³ A=sin³ A
Given, 3 sin 10 °- 4 sin 3 10 °
So, sin³ A i.e sin 30
= ½
Question 7
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=

A
cos(A/2)

B
tan(A/2)

C
cot(A/2)

D
sin(A/2)

Solution
Question 8
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What is the value of Sin 6X ?

A
-3 Sin2X

B
sin3Xcos3X

C
3sin2X

D
2sin3Xcos3X
Question 9
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In a triangle ABC, sin 2A = ?

A
2sin(B+C)cos( B-C)

B
2sin(B-C)cos( B-C)

C
2sin( B-C)cos(B+C)

D
-2sin(B+C)cos( B+C)

Solution

= -2 Sin (B+C)Cos(B+C) , as cos (180 - x) = - cosx
Question 10
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In a triangle ABC, if angle A = 72 °, angle B = 48 °and c = 9 cm then the Ĉis

A
45

B
120

C
60

D
90

Solution

In any traingle The sum of 3 sides of a traingle is equal to 180 °
Given
A=72 °
B=48 °
A+B+C=180 °
72 °+48 °+C=180 °
C=180 °-120 °
C=60 °