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Principles of Inheritance & Variation Test 4

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Principles of Inheritance & Variation Test 4
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  • Question 1
    1 / -0

    When alleles of two contrasting characters are present together, one of the character express and the other remains hidden. This is the________.

    Solution

    When alleles of two contrasting characters are hybridized together, one of the character express and the other remains hidden .This is Mendel’s first law or law of dominance.

  • Question 2
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    The genotypic ratio of a monohybrid cross is____.

    Solution

    The genotype is the actual genetic makeup of an individual. In monohybrid cross the genotypic ration is 1:2:1 and phenotypic ratio is 3:1.

  • Question 3
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    The geometrical device that helps to find out all the possible combinations of male and female gametes is called?

    Solution

    Punnett square is used to find out all the possible combination of male and female gametes. In monohybrid cross, a square of four is used and in dihybrid square of 16 is used.

  • Question 4
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    Which of the following terms represent a pair of contrasting characters?

    Solution

    A pair of contrasting characters of same plant is calledallelomophs. Alleles separate from each other during gamete formation and goes to different gametes.

  • Question 5
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    The crossing of F1 to any one of the parents is called?

    Solution

    The crossing of F1 to any one of the parents is called back cross. It is used to check the purity of individual. When F1 is crossed with recessive parent, it is called test cross.

  • Question 6
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    In a plant, red fruit (R) is dominant over yellow fruit (r) and tallness (T) is dominant over shortness (t). If a plant with RRTt genotype is crossed with a plant that is rrtt:

    Solution

    If a plant with RRTt genotype is crossed with a plant that is rrtt 50% of the offspring will be tall with red fruit.

  • Question 7
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    If two pea plants having red (dominant) coloured flowers with unknown genotypes are crossed, 75% of the flowers are red and 25% are white. The genotypic constitution of the parents having red coloured flowers will be

    Solution

    When two pea plants having red (dominant)c coloured flowers with unknown genotype are crossed, the 75% red and 25% white flowered plants will be produced by following the law of Mendel. This is possible only if the parents are heterozygotes. 

  • Question 8
    1 / -0

    F2 generation in a Mendelian cross showed that both genotypic and phenotypic ratios are same as 1 : 2 : 1. It represents in case of

    Solution

    Monohybrid cross with incomplete dominance shows both genotypic and phenotypic ratio as same (1 : 2 : 1).

    Genotypic ratio - 1(AA):2(Aa):1(aa)
    Phenotypic ratio - 1(Red):2(Pink):1(White)

  • Question 9
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    Which of the following statements is true regarding the “law of independent assortment”?

    Solution

    Independent Assortment describes how different genes independently separate from one another when reproductive cells develop. Independent assortment of genes and their corresponding traits was first observed by Gregor Mendel. Recombination occurs during meiosis and is a process that breaks and recombines pieces of DNA to produce new  combinations of genes. Recombination scrambles pieces of maternal and paternal genes, which ensures that genes assort independently from one another.

  • Question 10
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    In Mendel's experiments with garden pea, round seed shape (RR) was dominant over Wrinkled Seeds (rr), Yellow cotyledon (YY) was dominant over green cotyledon (yy). What are the expected Phenotypes in the F2 generation of the cross RRYY x rryy?

    Solution

    The expected Phenotypes in the F2 generation of the cross RRYY x rryy is Round-yellow; wrinkled-yellow; round-green and wrinkled-green in 9:3:3:1 similar to dihybrid results.

  • Question 11
    1 / -0

    A person with unknown blood group under ABO system has suffered much blood loss in an accident and needs immediate blood transfusion. His one friend, who has a valid certificate of his own blood type, offers for blood donation without delay. What would have been the type of blood group of the donor friend?

    Solution

    A person with unknown blood group under ABO grouping should be given Type O blood group as O is universal donor and can be transfused to any person.

  • Question 12
    1 / -0

    A self-fertilizing trihybrid plant forms:

    Solution

    Self-fertilized plants are pure line and trihybrid plant will form 8 different kinds of gametes. These gametes undergo independent assortment to form 64 combination of zygote.

  • Question 13
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    In the hexaploid wheat, the haploid (n) and basic (X) numbers of chromosomes are _____.

    Solution

    In hexaploid wheat, the basic number of chromosome is 7 and haploid in hexaploid is 21 and as diploid will have 7x6 = 42 chromosome. Therefore, n=21 and X=7.

  • Question 14
    1 / -0

    In a given plant, red colour (R) of fruits is dominant over white fruit (r): and tallness (T) is dominant over dwarfness (t). If a plant with genotype RRTt is crossed with a plant of genotype rrtt, what will be the percentage of tall plants with red fruits in the next generation?

    Solution

    According to question, tallness (T) is dominant over dwarfism (t) and red colour (R) is dominant over white (r) fruit colour.

    Parent Generation; P1 : RRTt  x  rrtt

    F1 generation :

    Phenotypic ratio = 1  (tall plant, red fruit)         
    : 1 (dwarf plant, red fruit)
    ; thus, percent of tall plant with red fruit is 50%.

  • Question 15
    1 / -0

    What will be expected blood groups in the off spring when there is a cross between AB blood group mother and heterozygous B blood group father?

    Solution

    AB blood group of mother have two alleles IA and IB. The heterozygous B blood group of father has alleles IB and i. The possible outcome are IA IB,IAi,IBIB and IBi. That form AB, A, B and B blood group respectively.

  • Question 16
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    Assertion: An organism with lethal mutation may not even develop beyond the zygote stage.

    Reason: All types of gene mutations are lethal.

    Solution

    An organism with lethal mutation may not even develop beyond zygote stage due to change in gene but all kinds of mutations are not lethal. Mutation is main source of variation essential for evolution.

  • Question 17
    1 / -0

    Deviation from Medelism’s occurs due to
    a. Multiple alleles
    b. Co dominance
    c. Linkage and crossing over
    d. Independent assortment

    Solution

    Deviation from Medelism’s occurs due to co-dominance, multiple alleles, incomplete dominance in which single gene is not completely dominant over the other to produce dominant trait.

  • Question 18
    1 / -0

    Chromosomal theory of inheritance was experimentally verified by T.H.Morgan and his colleagues working with tiny flies:

    Solution

    T.H.Morgan worked on the tiny fruit fly called Drosophila melanogaster. This tiny fly shows variation in eye colour and can be easily crossed with other to show the flow trait.

  • Question 19
    1 / -0

    Chromosome theory of XY sex determination was proposed by:

    Solution

    Chromosome theory of XY sex determination was proposed by Wilson and Stevens.

  • Question 20
    1 / -0

    Crossing over occurs at:

    Solution

    Crossing over occurs at four strand stage of panchytene of meiosis-I. Each homologous chromosome has two stands. Exchange of gene occurs during this period.

  • Question 21
    1 / -0

    Which organism’s male contain a pair of Z chromosome as sex chromosome besides autosomes?

    Solution

    In birds male contain a pair of Z chromosome as sex chromosome besides autosomes while female contain one Z and one W chromosome.

  • Question 22
    1 / -0

    Linkage is the_________.

    Solution

    Linkage is the physical association of two genes present on same chromosome. Genes located close to each other have high linkage percentage.

  • Question 23
    1 / -0

    On the basis of sex chromosome shown below, the bird shown is:

    Solution

    Male birds bears ZZ sex chromosome as sex determination is ZO type, in which ZZ is male and ZO is female.

  • Question 24
    1 / -0

    Two genes p and q showing 1.3% of recombination while other two genes x and y show 37.2 percent of recombination. Which pair of genes is close to each other?

    Solution

    Two genes p and q showing 1.3% of recombination while other two genes x and y show 37.2 percent of recombination. p and q genes are present close to each other as they show less recombination percentage.

  • Question 25
    1 / -0

    Assertion: In human beings, 23 pairs of chromosomes are present in diploid cells.

    Reason: 22 pairs of chromosomes are equal in male and female but a pair sex chromosome is different in them.

    Solution

    In human beings, 23 pairs of chromosomes are present in diploid cells.
    Twenty two pairs of chromosomes are equal in male and female but a pair sex chromosome is different in them. Male contain XY and female contain XX sex chromosome.

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