Some Basic Concepts Of Chemistry Test

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Some Basic Concepts Of Chemistry Test - 8

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Weekly Quiz Competition

Question 1
4 / -1

Few figures are expressed in scientific notation.Mark the incorrect one.

A
234000 = 2.34 x 10⁵

B
8008 = 8 x 10⁸

C
0.0048 = 4.8 x 10^-3

D
500.0 = 5.00 x 10²

Solution

8008 = 8.008 x 10³
Question 2
4 / -1

Mark the rule which is not correctly stated about the determination of significant figures.

A
Zeros preceding to first non-zero digit are not significant

B
Zeros between two non-zero digits are not significant

C
Zeros at the end or right of the number are significant if they are on the right side of the decimal point

D
All non-zero digits are significant

Solution

Zero between two non - zero digits are significant.
Question 3
4 / -1

Which of the following rules regarding the significant figures and calculations involving them is not correct?

A
The result of an addition or subtraction is reported to the same number of decimal places as present in number with least decimal places

B
Result of multiplication or division should have same number of significant figures as present in most precise figure

C
The result of multiplication or division should be rounded off to same number of significant figures as present in least precise figure

D
The non-significant figures in the measurements are rounded off

Solution

Answer to a multiplication or division is rounded off to the same number of significant figures as possessed by the least precise term in the calculation.
Question 4
4 / -1

The result of the operation 2.5 x 1.25 should be which of the following on the basis of significant figures?

A
3.125

B
3.13

C
3.1

D
31.25

Solution

2.5 x 1.25 = 3.125
Since 2.5 has two significant figures, the result should not have more than two significant figures. Hence, the answer will be 3.1.
Question 5
4 / -1

How many significant figures are present in 0.010100 x 10³?

A
7

B
5

C
3

D
10

Solution

0.010100 x 10³ contains 5 significant figures.
Question 6
4 / -1

What will be the answer in appropriate significant figures as a result of addition of 3.0223 and 5.041?

A
80.633

B
8.0633

C
8.063

D
806.33

Solution

3.0223 + 5.041 = 8.0633
Since, 5.041 has only 3 digits after the decimal point, the result should be reported to 3 digits after decimal point.
Question 7
4 / -1

Which of the following is the most accurate measurement?

A
9m

B
9.0m

C
9.00m

D
9.000m

Solution

9.000 m is the most accurate measurement as it is most precise among the given options.
Question 8
4 / -1

Which of the following options is not correct?

A
2.300 + 0.02017 + 0.02015 = 2.340

B
126. 000 has 3 significant figures

C
15.15 μs = 1.515 x 10^-5s

D
0.0048 = 48 x 10^-3

Solution

0.0048 = 4.8 x 10^-3
Question 9
4 / -1

What should be the volume of the milk (in m³) which measures 5 L?

A
5 x 10^-3 m³

B
5 x 10³ m³

C
5 x 1000 m³

D
5 x 10⁶ m³

Solution

Since 1 L = 1000 cm³ and 1 m = 100 cm
Question 10
4 / -1

How many seconds are there in 3 days?

A
259200 s

B
172800 s

C
24800 s

D
72000 s

Solution

Seconds in 3 days can be calculated as

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Some Basic Concepts Of Chemistry Test - 8

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Question 1

234000 = 2.34 x 105

8008 = 8 x 108

0.0048 = 4.8 x 10-3

500.0 = 5.00 x 102

Solution

Question 2

Zeros preceding to first non-zero digit are not significant

Zeros between two non-zero digits are not significant

Zeros at the end or right of the number are significant if they are on the right side of the decimal point

All non-zero digits are significant

Solution

Question 3

The result of an addition or subtraction is reported to the same number of decimal places as present in number with least decimal places

Result of multiplication or division should have same number of significant figures as present in most precise figure

The result of multiplication or division should be rounded off to same number of significant figures as present in least precise figure

The non-significant figures in the measurements are rounded off

Solution

Question 4

3.125

3.13

3.1

31.25

Solution

Question 5

7

5

3

10

Solution

Question 6

80.633

8.0633

8.063

806.33

Solution

Question 7

9m

9.0m

9.00m

9.000m

Solution

Question 8

2.300 + 0.02017 + 0.02015 = 2.340

126. 000 has 3 significant figures

15.15 μs = 1.515 x 10-5 s

0.0048 = 48 x 10-3

Solution

Question 9

5 x 10-3 m3

5 x 103 m3

5 x 1000 m3

5 x 106 m3

Solution

Question 10

259200 s

172800 s

24800 s

72000 s

Solution

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234000 = 2.34 x 10⁵

8008 = 8 x 10⁸

0.0048 = 4.8 x 10^-3

500.0 = 5.00 x 10²

15.15 μs = 1.515 x 10^-5s

0.0048 = 48 x 10^-3

5 x 10^-3 m³

5 x 10³ m³

5 x 1000 m³

5 x 10⁶ m³