Hydrocarbons Test

Result

Hydrocarbons Test - 25

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Weekly Quiz Competition

Question 1
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Direction (Q. Nos. 1 - 8) This section contains 8 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.
Q. Which of the following reaction would not give atleast one aldehyde product?

A

B

C

D

Solution

Correct answer is c because when we oxidise 1 pentyne with KMnO4 in basic medium, we will get a salt of a carboxylic acid.
Question 2
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Which set of reagent(s) in correct order would accomplish the following transformation?

A
a

B
b

C
c

D
d
Question 3
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The major product of the following reaction is

A

B

C

D
Question 4
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What is the final major product of the following reaction?

A

B

C

D
Question 5
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Predict major product of the following reaction.

A

B

C

D
Question 6
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What is true about the final major product of the reaction?

A
A meso-2, 3-dichlorobutane

B
A pure enantiomer of 2, 3-dichlorobutane

C
A racemic mixture of 2, 3-dichlorobutane

D
Both meso and racemic 2, 3-dichlorobutane
Question 7
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A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?

A
Treatment with Pd/CaCO₃/H₂ would make it achiral

B
Treatment with Na/NH₃ (l) would make it achiral

C
Treatment with Raney nickel-H₂ would make it achiral

D
It’s reaction with HgSO₄/ H₂SO₄(aq) gives a mixture of ketones

Solution

A chiral hydrocarbon -Na → H₂
There is terminal triple bond in the reactant hydrocarbon because,
R - C ≡ C - H -NaR - C ≡ O Na⁺+H₂
Molecular mass = 8²i.e., It is C₆H₁₀

(a) CH3 - CH2 - CH - C ≡ CH
|
CH3
H2 | Pd | CaCO3
CH3 - CH2 - *CH - CH = CH2
|
CH3
Option A is wrong as it is chiral

CH3 - CH2 - CH - C ≡ CH
|
CH3
Na| NH3

CH3 - CH2 - *CH - CH = CH2
|
CH3
Option B is wrong as it is chiral
CH3 - CH2 - CH - C ≡ CH
|
CH3
H2 | Ni
CH3 - CH2 - CH - CH2 = CH2
|
CH3
Option C is correct as it is achiral
Question 8
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A hydrocarbon X (C₁₄H₂₂)o n treatm ent with H₂/Pt gives C₁₄H₂₆. Also X on treatm ent with alkaline KMnO₄ followed by hydrolysis of products yields C₇H₁₂O₂ which on further heating with soda lime gives cyclohexane. Hence, X is

A

B

C

D

Solution

The correct answers are option B.
As only 4 hydrogen atoms are increased after hydrogenation, there should be only 1 3× bond. So option B is correct.
Question 9
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Direction (Q. Nos. 9 - 10) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.
Q. Column I has some alkynes and Column II has their corresponding reaction products. Match them appropriately.

A
a

B
b

C
c

D
d
Question 10
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Column I has some reactions and Column II has the characteristics of reactions and products of Column I. Match them appropriately.

A
a

B
b

C
c

D
d