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Coordination Compounds Test - 9

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Coordination Compounds Test - 9
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  • Question 1
    1 / -0

    When 0.1 mol of CoCl3(NH3)5 is treated with excess of AgNO3, 0.2 mol of AgCl is obtained. The conductivity of the solution will correspond to

  • Question 2
    1 / -0

    In the equation 4M + 8CN- + 2H2O + O2 → 4[M(CN)2]- + 4OH-, the metal ion is

    Solution

    Silver is extracted by cyanide process and thus, M is silver.

     

  • Question 3
    1 / -0

    ____ EDTA molecule(s) is/are required to make an octahedral complex with a Ca2+ ion.

    Solution

    EDTA is a hexadentate ligand, so only one EDTA molecule is required to form an octahedral complex.

     

  • Question 4
    1 / -0

    Match the compounds given in Column I with the oxidation state of cobalt present in them (given in Column II) and choose the correct answer.
     

    Column I (Compound) Column II (Oxidation state of Co)
    A. [Co(NCS)(NH3)5](SO3) 1. +4
    B. [Co(NH3)4Cl2]SO4 2. 0
    C. Na4[Co(S2O3)3] 3. +1
    D. [Co2(CO)8] 4. +2
    5. +3
    Solution
    Column I (Compound) Column II (Oxidation state of Co)
    [Co(NCS)(NH3)5](SO3) +3
    [Co(NH3)4Cl2]SO4 +4
    Na4[Co(S2O3)3] +2
    [Co2(CO)8] 0


     

  • Question 5
    1 / -0

    Which of the following pairs of 'coordination compound - IUPAC name' are correct?

    a. [CoCl(NH3)5]CO3 - chloropentaammine cobalt (III) carbonate
    b. K2[Zn(OH)4] - potassium tetrahydroxozincate (II)
    c. [Pt(py)4][PtCl4] - tetrapyridineplatinum (II) tetrachloroplatinate (II)
    d. K4[Ni(CN)4] - potassium tetracyanonickel (0)

    Solution

    Correct answer is 'b and c'.

    a. [CoCl(NH3)5]CO3 - pentaamminechlorocobalt (III) carbonate

    d. K4[Ni(CN)4] - potassium tetracyanonicklate (0)

     

  • Question 6
    1 / -0

    Facial and meridional isomerism will be exhibited by

    Solution

    Complexes of the type MA3B3 exhibit meridional and facial isomerism.

     

  • Question 7
    1 / -0

    [CoBr(NH3)5]SO4 and [CoSO4(NH3)5]Br are

    Solution

    [CoBr(NH3)5]SO4 and [CoSO4(NH3)5]Br are ionization isomers.

     

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