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Haloalkanes and Haloarenes Test 3

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Haloalkanes and Haloarenes Test 3
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  • Question 1
    1 / -0

    Alkyl halides are insoluble in water

    Solution

    The force of attraction between the alkyl halide and water is weaker and cannot overcome the force of attraction between alkyl halide and alkyl halide as also that of water and water molecules.

  • Question 2
    1 / -0

    The most common freons in industrial use is manufactured by

    Solution

    Most common Freon is synthesized by Swartz reaction.

  • Question 3
    1 / -0

    The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol with

    Solution

    This is SN2 reaction.

  • Question 4
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    AgCN reacts with haloalkanes to form isocyanide. Haloalkanes react with KCN to form alkyl cyanides as main product

    Solution

    AgCN is covalent in nature while KCN is ionic so KCN produces CN- in the solution.

  • Question 5
    1 / -0

    Dichloromethane (Methylene chloride) is

    Solution

    CHCl2 is organic solvent

  • Question 6
    1 / -0

    Which one of the following forms propanenitrile as the major product?

    Solution

  • Question 7
    1 / -0

    Bromomethane, Chloromethane, Dibromomethane, 1 – Chloropropane, Isopropyl chloride, 1 – Chlorobutaneare all

    Solution

    These all are covalent compounds hence are soluble in organic solvents.

  • Question 8
    1 / -0

    In the reaction, R – X + NaOR’ → ROR’ + X (– ve ion). The main product formed is

    Solution

    This is normal substitution reaction.

  • Question 9
    1 / -0

    Hydrocarbons are prepared from Grignard reagent by

    Solution

    Grignard reagent abstracts acidic hydrogen from H2O forming alkane.

  • Question 10
    1 / -0

    Which one of the following is employed as antityphoid drug?

    Solution

    Chloramphenicol is antityphoid drug.

  • Question 11
    1 / -0

    CH3=CH2CH3 + H – I → CH3CH2CH2I + CH3CHICH3 (major). This reaction is

    Solution

    This is electrophilic addition reaction following Markovnikoffs rule.

  • Question 12
    1 / -0

    Grignard reagent should be prepared under anhydrous conditions because

    Solution

    R—MgX is very reactive.

  • Question 13
    1 / -0

    If ‘n’ represents total number of asymmetric carbon atoms in a compound, the possible number of optical isomers of the compound is

    Solution

    The correct answer is Option C.

    The general formula for calculating stereoisomers is: 2n, where n is the number of chiral centers.
    Stereoisomers are compounds with the same chemical formula but different spatial arrangement and chiral centers are carbons that are bonded to 4 different groups. So, the possible no of optical isomers can be 2n.

  • Question 14
    1 / -0

    Chlorination of ethane is carried out in presence of

    Solution

    Chlorination of ethane is carried out in the presence of Ultraviolet light to form 1,2-hexachloro ethane. 

  • Question 15
    1 / -0

    Which one of the following is a synthetic halogen compound?

    Solution

    Chloroquine is a synthetic halogen compound.

  • Question 16
    1 / -0

    Finkelstein reaction is

    Solution

    Halide exchange reaction is Finkelstein reaction in which alkyl chloride is converted to alkyl iodide.

  • Question 17
    1 / -0

    Name the following aryl halide as per the IUPAC system

    Solution

    At position 1 chloro group is present and at 2-methylpropyl is present.

  • Question 18
    1 / -0

    Carbon tetra chloride has a dipole moment_____.

    Solution

    CCl4 is symmetrical hence dipole moment is zeo.

  • Question 19
    1 / -0

    Decreasing order of reactivity of hydrogen halide acids in the conversion of ROH →RX is

    Solution

    I−is very good nucleophile.

  • Question 20
    1 / -0

    Chlorination of ethane is carried out in presence of

    Solution

    The correct answer is option C
    Chlorination of ethane is carried out in the presence of Ultraviolet light to form 1,2-hexachloroethane.                             
    CH3CH3   ----- UVlight ---->      CCl3CCl3
    So, the correct answer is C.
     

  • Question 21
    1 / -0

    A hydrocarbon C5H10 does not react with chlorine in dark but gives a single monochloro compound C5H9Cl in bright sunlight. The hydrocarbon is

    Solution

    A hydrocarbon with the molecular formula, C5H10 belongs to the group with a general molecular formula CnH2n. Therefore, it may either be an alkene or a cycloalkane. Since hydrocarbon does not react with chlorine in the dark, it cannot be an alkene. Thus, it should be a cycloalkane. Further, the hydrocarbon gives a single monochloro compound, C5H9Cl by reacting with chlorine in bright sunlight. Since a single monochloro compound is formed, the hydrocarbon must contain H−atoms that are all equivalent. Also, as all H−atoms of a cycloalkane are equivalent, the hydrocarbon must be a cycloalkane. Hence, the said compound is cyclopentane.

  • Question 22
    1 / -0

    Which branched chain isomer of the hydrocarbon with molecular mass 72u gives only one isomer of mono substituted alkyl halide?

    Solution

    Neopentane has all same type of hydrogen and has molecular weight 72u

  • Question 23
    1 / -0

    Methyl bromide is converted into ethane by heating it in ether medium with

    Solution

  • Question 24
    1 / -0

    p – Dichlorobenzene has than those of o – and m – isomers

    Solution

    Halogens are deactivators but yet o/p director.

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