Atomic Structure Test

Result

Atomic Structure Test - 16

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Weekly Quiz Competition

Question 1
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Direction (Q. Nos. 1-8) This section contains 8 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. FM radio broadcasts at 900 kHz. What wavelength does this corresponds to?

A
333 m

B
3.03 x 10^-3m

C
330 m

D
3300 m

Solution
Question 2
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The nucleus of helium contains

A
  Four protons

B
  Four neutrons

C
  Four protons and two electrons

D
  Two neutrons and two protons

Solution

A helium nucleus is made of two protons and two neutrons and has a charge +2.
Question 3
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Moseley’s equation is represented as where, a and b are constants.
Q. If OA = 1, then atomic number of the element showing frequency of 400 Hz is

A
21

B
11

C
401

D
19

Solution

Thus, graph is a straight line
Question 4
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A gas absorbs photon of wavelength 355 nm and emits at two wavelengths. If one of the emissions is at 680 nm, the other is at
[AlEEE 2011]

A
1035nm

B
325 nm

C
743 nm

D
518 nm

Solution

Absorbed energy = Emitted energy
Question 5
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The longest wavelength of light capable of breaking a single (Cl — Cl) bond in Cl₂ is if
[AlEEE 2010]

A
494 pm

B
494 nm

C
494 Å

D
247 m

Solution

ΔH = 242 kJ mol^-1
Question 6
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Which of the following conclusions could not be derived from Rutherford’s α-particle scattering experiment?

A
Electrons and nucleus are held together by electrostatic forces of attraction.

B
The radius of the atom is larger than that of the nucleus.

C
Most of the space in the atom is empty.

D
Electrons move in a circular path of fixed energy. Circular paths are called orbits.

Solution

Option A: Electrons (-) and nucleus (+) are held together by electrostatic forces of attraction.
Option B: Radius of the atom (= 10^-10m) > radius of the nucleus (10^-15m).
Option C: Most of the space is empty as given by the radius of the nucleus and atom.
Option D: As electron moves in a circular path, it emits energy and ultimately falls into the nucleus.
Thus, the correct option is D.
Question 7
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Which of the following statements is not correct about the characteristics of cathode rays?

A
They start from the cathode and move towards the anode.

B
They travel in straight line in the absence of an external electrical or magnetic field.

C
Characteristics of cathode rays do not depend upon the material of electrodes in cathode ray tube.

D
Characteristics of cathode rays depend upon the nature of gas present in the cathode ray tube.

Solution

(d) Cathode rays consist of negatively charged material particles called electron. They were discovered by William Crookes. The characteristics of cathode rays do not depend upon the material of electrodes and the nature of the gas present in the cathode ray tube.
Question 8
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Energy of a mole of radio wave photons with a frequency of 909 kHz is

A
6.02 x 10^-28J

B
3.62 x 10^-4J

C
1.00 x 10^-4J

D
6.02 x 10^-31J

Solution

E = N₀hv
⇒ E = 6.02 x 10²³ x 6.62 x 10^-34 x 909 x10³= 3.62 x 10^-4 J
Question 9
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Direction (Q. Nos. 9 and 10) This section contains a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given ptions (a),(b),(c),(d)
A hypothetical electromagnetic wave is pictured here.

Q. Energy associated with this wave is

A
4.24 x 10^-19J

B
2.12 x 10^-19J

C
1.06 x 10^-19J

D
8.49 x 10^-19J

Solution

A to E makes one complete wave.
Question 10
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A hypothetical electromagnetic wave is pictured here.

Q. A standing wave in a string 42 cm long has a total of six nodes (including those at the ends). Wavelength of the standing wave is

A
7.0 cm

B
16.8 cm

C
10.5 cm

D
5.25 cm

Solution

A to E makes one complete wave.

If there are n nodes including those at the ends, in a string of length /, then
Question 11
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Direction (Q. Nos. 11) Choice the correct combination of elements and column I and coloumn II are given as option (a), (b), (c) and (d), out of which ONE option is correct.

Q. The colours of visible light are at different wavelength. Match the wavelengths in Column I with their colours in Column II.

A
a

B
b

C
c

D
d

Solution

Thus, (i)(700nm) Red (u)
(ii) (600 nm) - Orange (t)
(iii) (580 nm) - Yellow (s)
(iv) (500nm) - Green (r)
(v) (460 nm) - Blue (q)
(vi) (400 nm) - Violet (p)