Self Studies

Biology Test 376

Result Self Studies

Biology Test 376
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies
Weekly Quiz Competition
  • Question 1
    4 / -1

    Match the following:

    A. Gills 1. Amphibians
    B. Book gills 2. Mammals
    C. Moist Skin 3. Insects
    D. Lungs 4. Limulus
    E. Trachea 5. Fishes
    Solution

    The correct answer is A-5, B-4, C-1, D-2, E-3

    Explanation:

    A. Gills - 5. Fishes:

    • Gills are the primary respiratory organs in fishes. They are specialized structures that extract oxygen from water as it passes over the gill membranes, allowing aquatic animals like fish to breathe.

    B. Book gills - 4. Limulus (Horseshoe crab):

    • Book gills are found in Limulus (horseshoe crabs). These structures are named "book gills" because they resemble pages of a book. They allow the animal to breathe underwater by exposing a large surface area to water, facilitating gas exchange.

    C. Moist Skin - 1. Amphibians:

    • Amphibians, such as frogs and salamanders, have moist, permeable skin that allows them to absorb oxygen directly from the environment. This type of respiration, called cutaneous respiration, is essential for amphibians, especially when they are in water or moist habitats.

    D. Lungs - 2. Mammals:

    • Mammals, including humans, rely on lungs for respiration. Lungs are specialized organs designed to exchange gases with the atmosphere. Oxygen is taken in, and carbon dioxide is expelled through the process of breathing.

    E. Trachea - 3. Insects:

    • Insects breathe through a system of tubes called tracheae. Air enters the body through tiny openings called spiracles and travels through the tracheal tubes, delivering oxygen directly to the tissues and cells, which is different from blood-based respiration in vertebrates.

    Hence, the correct answer is A-5, B-4, C-1, D-2, E-3.

     

  • Question 2
    4 / -1

    Which one of the following is showing the correct sequential order of vertebrae in the vertebral column of human beings?

    Solution

    The correct answer is option 4.

    Explanation: 

    • It is well-known fact that the vertebral column of vertebrates is the modification of the notochord.

    • It is to be noted that the length of the human vertebral column is 71 cm in males and 61 in females.

    • In a fetus, there is only a single anterior concave curve, however, in adults, there are 4 curves cervical, thoracic, lumbar, and sacral.

    • The cervical curve is formed by 7 cervical vertebrae that start the vertebral column, then we have the thoracic vertebrae which are formed by 12 thoracic vertebrae.

    • Then the lumbar is formed by 5 lumbar vertebrae then there is the sacrum which forms the sacral vertebrae and then there is the coccyx.

    • Therefore, the correct sequence of vertebrae in the vertebral column is Cervical — thoracic — lumbar — sacral — coccygeal.

    • Hence, the correct answer is option 4.

     

  • Question 3
    4 / -1

    Floridean starch is the stored food in

    a. Fucus

    b. Volvox

    c. Chara

    d. Polysiphonia

    Solution

    The correct answer is d (Polysiphonia only)

    Explanation:

    • The members of Rhodophyceae are commonly called red algae.

    • The food is stored as Floridian starch which is very similar to amylopectin and glycogen in structure.

    • Examples: Polysiphonia, Porphyra, Gracilaria, and Gelidium.

    Classes Common name Major pigments Examples
    Chlorophyceae Green algae Chlorophyll a and b, carotenoids and xanthophyll  Chlamydomonas, Volvox, Ulothrix, Spirogyra, and Chara
    Phaeophyceae Brown algae Chlorophyll a and c, Fucoxanthin, flavoxanthin  Ectocarpus, Dictyota, Laminaria, Sargassum, and Fucus 
    Rhodophyceae Red algae Chlorophyll a and d, phycoerythrin, phycocyanin Polysiphonia, Porphyra, Gracilaria, and Gelidium

     

  • Question 4
    4 / -1

    Which of the following is/are correct for Protista?

    1. This group includes many kinds of unicellular prokaryotic organisms.

    2. Their mode of nutrition can be autotrophic or heterotrophic.

    3. Examples are unicellular algae, diatoms and protozoans.

    Solution

    The correct answer is 2 and 3

    Explanation:

    • Kingdom Protista: This kingdom includes a diverse group of mostly unicellular eukaryotic organisms. Protists have a well-defined nucleus and membrane-bound organelles.

    • Cellularity and Type: Protists are primarily unicellular, but they are eukaryotic, not prokaryotic. Therefore, they have a defined nucleus.

    • Mode of Nutrition: The mode of nutrition in Protists can be either autotrophic (e.g., photosynthetic algae) or heterotrophic (e.g., protozoans that ingest food particles).

    • Examples: Examples of Protists include unicellular algae (such as Chlamydomonas), diatoms, and protozoans (such as Amoeba and Paramecium).

     

  • Question 5
    4 / -1

    Assertion (A): In epigynous flowers, the ovary is superior.

    Reason (R): The margin of the thalamus grows upward and encloses the ovary completely in epigynous flowers.

    In the light of above statement, choose the correct option:

    Solution

    The correct answer is A is false but R is true.

    Explanation:

    • Epigynous flower:

      • In epigynous flowers, the ovary is inferior, not superior.

      • The floral parts such as petals, sepals, and stamens appear to arise from the top of the ovary, indicating that the ovary is positioned below the attachment of these parts.

      • The margin of the thalamus or the floral cup grows upward and encloses the ovary completely, leading to this characteristic arrangement.

      • Examples include Apple, Cucumber, and Sunflower.

    • Superior and inferior ovary:

      • Superior ovary: The ovary is positioned above the point of attachment of other floral parts. This can be found in hypogynous and perigynous flowers. Examples include Tomato and Lily.

      • Inferior ovary: The ovary is positioned below the point of attachment of other floral parts. This is characteristic of epigynous flowers.

    Therefore, the correct answer is A is false but R is true.

     

  • Question 6
    4 / -1

    Directions For Questions

    Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R)

    Assertion: Unmyelinated nervefibre is enclosed by Schwann cell

    Reason: Schwann cell are absent in myelinated nerve fibre.

    ...view full instructions

    In the light of the above statements, choose the correct answer from the options given below :

    Solution

    The correct answer is (A) is true but (R) is false

    Explanation:

    • Nerve fibers can be classified into myelinated and unmyelinated fibers based on the presence of a myelin sheath.

    • Myelinated nerve fibers have a myelin sheath, which is a fatty layer that insulates the axon and allows for faster transmission of nerve impulses.

    • Unmyelinated nerve fibers do not have a myelin sheath and thus conduct impulses more slowly.

    • Schwann cells are glial cells in the peripheral nervous system that play a crucial role in the formation and maintenance of the myelin sheath.

    • The myelinated nerve fibres are enveloped with Schwann cells, which form a myelin sheath around the axon.

    • Unmyelinated nerve fibre is enclosed by a Schwann cell that does not form a myelin sheath around the axon.

    Assertion (A): Unmyelinated nerve fiber is enclosed by Schwann cell.

    • This statement is true because even in the absence of a myelin sheath, Schwann cells still surround and support unmyelinated nerve fibers. The Schwann cells provide metabolic support and protection to these fibers.

    Reason (R): Schwann cells are absent in myelinated nerve fibers.

    • This statement is false because Schwann cells are present in myelinated nerve fibers. Schwann cells are responsible for creating the myelin sheath around the axons of myelinated nerve fibers. They wrap their membrane around the axon multiple times to form the insulating layer.

     

  • Question 7
    4 / -1

    Select the correct sentence(s).

    a. The release of energy in the aerobic process is a lot greater than in the anaerobic process.

    b. ATP is broken down giving rise to a fixed amount of energy which can drive the endothermic reactions taking place in the cell.

    c. The pyruvate is converted into lactic acid which is also a three-carbon molecule.

    Solution

    The correct answer is option 3.

    Key Points

    • The release of energy in the aerobic process is significantly greater than in the anaerobic process.

    • ATP (Adenosine Triphosphate) is broken down to release a fixed amount of energy which can drive the endothermic reactions taking place in the cell.

    • Pyruvate, a three-carbon molecule, is converted into lactic acid, which is also a three-carbon molecule during anaerobic respiration.

    • In aerobic respiration, glucose is fully oxidized to carbon dioxide and water, producing a high yield of ATP.

    • Anaerobic respiration is less efficient and results in the production of less ATP and byproducts like lactic acid or ethanol.

     

  • Question 8
    4 / -1

    Oxygen released during photosynthesis comes from which among the following?

    Solution

    The correct answer is Water.

    Key Points

    • During the process of photosynthesis, plants convert light energy into chemical energy.

    • In the presence of sunlight, plants absorb carbon dioxide from the air and water from the soil.

    • Water molecules are split into hydrogen and oxygen atoms in the presence of light energy through a process called photolysis.

    • The oxygen atoms combine to form molecular oxygen (O2), which is then released into the atmosphere.

    • Thus, the oxygen released during photosynthesis comes from the water molecules.

     

  • Question 9
    4 / -1

    Assertion (A): Oxygen gets bound to haemoglobin of blood present in capillaries around alveoli and gets dissociated at the tissues.  

    Reason (R): Factors favourable for formation of oxyhaemoglobin are high pO2, low pCO2, lesser H+ concentration and lower temperature whereas in the tissues low pO2, high pCO2, high H+ concentration and higher temperature are favourable for dissociation of oxygen from oxyhaemoglobin. 

    In the context of above statements, select the correct one:

    Solution
    • Assertion (A) - TRUE

      • Alveoli are the tiny air sacs found at the end of bronchioles in the lungs.

      • These are the sites of oxygen and carbon dioxide exchange between the lungs and blood during inhalation and exhalation respectively.

      • In the pulmonary blood capillaries around alveoli, oxygen gets bound to hemoglobin forming oxyhaemoglobin.

      • In the tissues, oxygen gets dissociated from haemoglobin.

    • Reason (R) - TRUE 

      • In the lungs, conditions such as high pO2, low pCO2, lesser H+ concentration and lower temperature facilitate the binding of oxygen with hemoglobin to form oxyhemoglobin.

      • Anatgonistic factors such as low pO2, high pCO2, high H+ concentration and higher temperature facilitate the dissociation of O2 from the haemoglobin.

      • Due to this the oxygen requirement of tissues is fulfilled.

    Thus, both the assertion (A) and reason (R) are true and reason (R) is the correct explanation of the given assertion (A).

    So the correct answer is option 1.

     

  • Question 10
    4 / -1

    Flow of electron through photosynthetic ETC is

    Solution

    The correct answer is Initially uphill then downhill

    Concept:

    During the process of photosynthesis, particularly in the light reactions, the flow of electrons through the photosynthetic electron transport chain (ETC) involves both uphill and downhill movement of electrons.

    1. Initially Uphill: The electrons are excited by the absorption of light energy in the photosystems. Specifically, in Photosystem II (PSII), photons are absorbed by chlorophyll molecules causing electrons to be excited to a higher energy state (uphill process). These high-energy electrons are then passed to the primary electron acceptor.

    2. Then Downhill: After the electrons are excited (uphill), they travel down the electron transport chain through various proteins and carriers, such as plastoquinone, cytochrome b6f complex, and plastocyanin. As they move through the chain, they release energy which is used to pump protons across the thylakoid membrane, creating a proton gradient that is used to generate ATP. The electrons eventually reach Photosystem I (PSI), where they are re-excited by light energy and again move downhill through the chain to ultimately reduce NADP+ to NADPH

    Explanation:

    • This whole scheme of transfer of electrons, starting from the PS II, uphill to the acceptor, down the electron transport chain to PS I, excitation of electrons, transfer to another acceptor, and finally down hill to NADP+ reducing it to NADPH + H+ is called the Z scheme, due to its characterstic shape

     

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now