Chemistry Test 115

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Chemistry Test 115

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Weekly Quiz Competition

Question 1
4 / -1

The CFSE of octahedral [CoCl₆]^–4 is 18,000 cm^–1. The CFSE for tetrahedral [CoCl₄]^–2 will be :-

A
20,000 cm^–1

B
16,000 cm^–1

C
8,000 cm^–1

D
18,000 cm^–1

Solution

Δ_t = 4/9 × Δ₀

= 4/9 × 18000

= 8000 cm^–1
Question 2
4 / -1

N(CH₂CH₂NH₂)₃ ligand is :-

A
Bidentate

B
Tridentate

C
Tetradentate

D
Pentadentate

Solution

N(CH₂ CH₂ NH₂)₃ is tetradentate ligand because it has 4 N-atom as donor site.
Question 3
4 / -1

Out of TiF₆^2–, CoF₆^3–, Cu₂Cl₂ and NiCl₄^2– colourless species are :

A
CoF₆^3– and NiCl₄^2–

B
TiF₆^2– and CoF₆^2–

C
Cu₂Cl₂ and NiCl₄^2–

D
TiF₆^2– and Cu₂Cl₂

Solution

TiF₆^–2 and Cu₂Cl₂

Ti⁺⁴ = 3s²3p⁶ → No unpaired el^–

Cu⁺ = 3d¹⁰ → No unpaired el^–
Question 4
4 / -1

Highest C–O bond length will be in

A
[Mn(CO)₆]⁺

B
[Cr(CO)₆]

C
[V(CO)₆]^–

D
same in all
Question 5
4 / -1

In which compound synergic effect is present ?

A
[Ni(CO)₄]

B
[NiCl₄]^–2

C
[CuCl₄]^–2

D
[Mn(H₂O)₆]⁺²
Question 6
4 / -1

What is the correct order of C–O bond length :-

A

B

C

D
Question 7
4 / -1

Choose the incorrect option regarding following complex is :-

A
z > x Bond length

B
dsp² hybridisation

C
O.S. of Pt = +2

D
C-C bond length in this complex is less than individual CH₂=CH₂

Solution

Due to synergic bonding in CH₂ = CH₂
Question 8
4 / -1

What is the primary valency of Co in [Co(H₂O)₅Cl]Cl₂ :-

A
1

B
2

C
3

D
4
Question 9
4 / -1

Which of the following complexes produce ppt. with AgNO₃ and exist in two geometrical isomeric form :-

A
PtCl₂.4NH₃

B
PtCl₂.3NH₃

C
PtCl₄.4NH₃

D
PtCl₄.2NH₃
Question 10
4 / -1

The total number of chelate rings in [Ni(dmg)₂] are:

A
1

B
2

C
3

D
4

Solution

Chelate ring = 4 (5 membered & 6 membered)

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Re-Attempt Weekly Quiz Competition

Chemistry Test 115

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Chemistry Test 115

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SHARING IS CARING

Question 1

20,000 cm–1

16,000 cm–1

8,000 cm–1

18,000 cm–1

Solution

Question 2

Bidentate

Tridentate

Tetradentate

Pentadentate

Solution

Question 3

CoF63– and NiCl42–

TiF62– and CoF62–

Cu2Cl2 and NiCl42–

TiF62– and Cu2Cl2

Solution

Question 4

[Mn(CO)6]+

[Cr(CO)6]

[V(CO)6]–

same in all

Question 5

[Ni(CO)4]

[NiCl4]–2

[CuCl4]–2

[Mn(H2O)6]+2

Question 6

Question 7

z > x Bond length

dsp2 hybridisation

O.S. of Pt = +2

C-C bond length in this complex is less than individual CH2=CH2

Solution

Question 8

1

2

3

4

Question 9

PtCl2.4NH3

PtCl2.3NH3

PtCl4.4NH3

PtCl4.2NH3

Question 10

1

2

3

4

Solution

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20,000 cm^–1

16,000 cm^–1

8,000 cm^–1

18,000 cm^–1

CoF₆^3– and NiCl₄^2–

TiF₆^2– and CoF₆^2–

Cu₂Cl₂ and NiCl₄^2–

TiF₆^2– and Cu₂Cl₂

[Mn(CO)₆]⁺

[Cr(CO)₆]

[V(CO)₆]^–

[Ni(CO)₄]

[NiCl₄]^–2

[CuCl₄]^–2

[Mn(H₂O)₆]⁺²

dsp² hybridisation

C-C bond length in this complex is less than individual CH₂=CH₂

PtCl₂.4NH₃

PtCl₂.3NH₃

PtCl₄.4NH₃

PtCl₄.2NH₃