Chemistry Test 26

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Chemistry Test 26

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Weekly Quiz Competition

Question 1
4 / -1

Heat required to raise the temperature of 1 mol of a substance by 1^oC is called

A
Specific heat

B
Molar heat capacity

C
Water equivalent

D
Specific gravity

Solution

It is molar heat capacity.
Question 2
4 / -1

In an irreversible process taking place at constant T and P and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria

A
(dS)_{V, E} < 0, (dG)_{T, P} < 0

B
(dS)_{V, E} > 0, (dG)_{T, P} < 0

C
(dS)_{V, E} = 0, (dG)_{T, P} = 0

D
(dS)_{V, E} = 0, (dG)_{T, P} > 0

Solution

(dS)_V,E> 0, (dG)_T,P < 0
Question 3
4 / -1

When ice melts into water, entropy

A
Becomes zero

B
Decreases

C
Increases

D
Remain same

Solution

When ice melts into water entropy increases because randomness increases when ice change into water and entropy is directly proportional to randomness.
Question 4
4 / -1

Which of the following are not state functions?

(I) q + W
(II) q
(III) W
(IV) H - TS

A
(I) and (IV)

B
(II), (III) and (IV)

C
(I,) (II) and (III)

D
(II) and (III)

Solution

The property of the system whose value depends only on the initial and final state of the system is called a state function. It is independent of the path.

As q + W = Internal energy (ΔE)

Therefore ,it is a state function .

Also, H –TS= Gibbs energy (G)

It is also a state function .

Heat (q) and work (W) are not state functions because they are path dependent.
Question 5
4 / -1

Any series of operations so carried out that at the end, the system is back to its initial state is called

A
Boyle’s cycle

B
Reversible process

C
Adiabatic process

D
Cyclic process

Solution

In cyclic process, a system in a given state goes through a series of different processes, but in the end returns to its initial state.

Hence, option D is correct.

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Chemistry Test 26

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Chemistry Test 26

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Question 1

Specific heat

Molar heat capacity

Water equivalent

Specific gravity

Solution

Question 2

(dS)V, E < 0, (dG)T, P < 0

(dS)V, E > 0, (dG)T, P < 0

(dS)V, E = 0, (dG)T, P = 0

(dS)V, E = 0, (dG)T, P > 0

Solution

Question 3

Becomes zero

Decreases

Increases

Remain same

Solution

Question 4

(I) and (IV)

(II), (III) and (IV)

(I,) (II) and (III)

(II) and (III)

Solution

Question 5

Boyle’s cycle

Reversible process

Adiabatic process

Cyclic process

Solution

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(dS)_{V, E} < 0, (dG)_{T, P} < 0

(dS)_{V, E} > 0, (dG)_{T, P} < 0

(dS)_{V, E} = 0, (dG)_{T, P} = 0

(dS)_{V, E} = 0, (dG)_{T, P} > 0