Chemistry Test 3

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Chemistry Test 3

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Weekly Quiz Competition

Question 1
4 / -1

In the formula of diazonium salt i.e. N₂⁺X^-, what can we use as X?

A
BF₄^-

B
HSO₄^-

C
both

D
none

Solution

In diazonium salt, we can use Cl^-, Br^-, HSO₄^-, BF₄^-, etc. in short, every negative anion is used as X.
Question 2
4 / -1

A secondary amine is a compound which possesses

A
two –NH₂ groups.

B
one –NH₂ group attached to a secondary carbon.

C
one –NH- group bounded to two alkyl or aryl group.

D
one –NH₂ group attached to the second carbon of the main carbon chain.

Solution

NH₂ is a primary amine

NH is a secondary amine

N is a tertiary amine.

N has 3 unpaired electrons. From which, one is bounded with hydrogen and two are remaining. Therefore, it can be bounded to two alkyls or aryl group.
Question 3
4 / -1

Which of the following is an antioxidant?

A
Butylated hydroxy toluene

B
Sodium meta by sulphide

C
Espartan

D
None of the above

Solution

Butylated hydroxyanisole, citric acid and ascorbic acid are some of the antioxidants which cause slow activity of oxygen, so that the food is preserved for a long time.
Question 4
4 / -1

The gas, which is used for artificial ripening of fruits, is

A
CH₄

B
C₂H₄

C
C₂H₆

D
none

Solution

Ripening is a process in fruits that causes them to become more palatable. In general, fruits become sweeter, less green and softer as it ripens. Ripening agents speed up the ripening process. Ethene or ethylene is used for ripening to speed up the process.
Question 5
4 / -1

Propanoyl chloride is isomeric with

A
Propanol

B
2-Chloropropanol

C
Dichloro-acetone

D
2-Chloropropanal

Solution

Molecular formula of Propanoyl chloride, CH₃-CH₂-COCl, is C₃H₅OCl

2-Chloropropanol, CH₃ - CH (Cl) - CH₂ - OH, is C₃H₇OCl

Propanol has no Cl, therefore, it can't be an isomer

Dichloro-acetone has 2 Cl. It cannot be an isomer either.

2-Chloropropanal, CH₃ - CH(Cl) - CHO, is C₃H₅OCl.

Hence, 2-Chloropropanal is the correct answer
Question 6
4 / -1

Which of the following is a method of preparation of alcohol?

A
Hydroboration oxidation

B
Lucas test

C
Fries rearrangement

D
Reimer – Tiemann

Solution

Lucas test is a formation of halo alkane from alcohol

(c) and (d) are the reaction of phenol

And hydroboration oxidation is one of the methods of preparation of alcohol.

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Chemistry Test 3

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Chemistry Test 3

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Question 1

BF4-

HSO4-

both

none

Solution

Question 2

two –NH2 groups.

one –NH2 group attached to a secondary carbon.

one –NH- group bounded to two alkyl or aryl group.

one –NH2 group attached to the second carbon of the main carbon chain.

Solution

Question 3

Butylated hydroxy toluene

Sodium meta by sulphide

Espartan

None of the above

Solution

Question 4

CH4

C2H4

C2H6

none

Solution

Question 5

Propanol

2-Chloropropanol

Dichloro-acetone

2-Chloropropanal

Solution

Question 6

Hydroboration oxidation

Lucas test

Fries rearrangement

Reimer – Tiemann

Solution

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BF₄^-

HSO₄^-

two –NH₂ groups.

one –NH₂ group attached to a secondary carbon.

one –NH₂ group attached to the second carbon of the main carbon chain.

CH₄

C₂H₄

C₂H₆