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NEET Test 167

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NEET Test 167
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Weekly Quiz Competition
  • Question 1
    4 / -1

    The height of a point vertically above the earth's surface at which the acceleration due to gravity becomes 9% of its value at the surface is (Given, = radius of earth)

    Solution

    Acceleration due to gravity at height h is given as

     

  • Question 2
    4 / -1

    Crop plants grown in monoculture are:

    Solution

    Monoculture is the agricultural practice of producing or growing a single crop or plant species over a wide area and for a large number of consecutive years. Monocultures can lead to the quicker spread of pests and diseases, where a uniform crop is susceptible to a pathogen. 'Crop monoculture' is the practice of growing the same crop year after year.

     

  • Question 3
    4 / -1

    Emasculation

    Solution

    Emasculation Prevent self-pollination in female parent.

    Emasculation:  Removal of stamens or anthers or killing the pollen of a flower without the female reproductive organ is known as emasculation. In bisexual flowers, emasculation is essential to prevent of self-pollination. In monoecious plants, male flowers are removed.

     

  • Question 4
    4 / -1

    Which of the following has a saprophytic mode of nutrition?

    Solution

    The nourishment of Mushroom is saprophytic, which is just like heterotrophic nutrition. This is the reason organisms like mushrooms nourish on a dead and decomposing plant or animal matter. Mushrooms prefer shadowy, cool, moist, and wet growing environments. They grow best in temperatures between 55- 60 degrees Fahrenheit, faraway from drying, direct heat, and drafts. Roundworms, leeches, and lice are parasites because they survive in a further organism and obtain their nutrition from them.

    There are so many mushroom spawn suppliers, which manufacture the quality-based fresh and dried mushrooms in the market with the best nutritional value.

     

  • Question 5
    4 / -1

    What is produced when  CH3CONH2 reacts with NaOBr? Is NaOBr a product of (or equivalent to) Br2+ NaOH which are used in the Hoffmann bromamide degradation reaction?

    Solution

    The product is CH3-NH2.

    This is an example of the Hofmann Degradation of primary amides to amines with one less carbon atom.

    The base abstracts an N-H proton, forming the conjugate base of the amide.

    Finally obtained product is:

     

     

  • Question 6
    4 / -1

    A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is

    Solution

     

  • Question 7
    4 / -1

    The oesophagus of the cockroach opens up into a sac like structure called the ____________.

    Solution

    The oesophagus of the cockroach opens up into a sac like structure called the crop.

    The crop is followed by the gizzard or proventriculus. Gizzard is thick walled, muscular and conical bulbous structure. It has an outer thick layer of circular muscles and a thick, inner cuticle forming six highly chitinous plates called teeth.

     

  • Question 8
    4 / -1

    A block of mass M is resting on an inclined plane as shown in the figure. The inclination of the plane to the horizontal is gradually increased. It is found that when the angle of inclination is θ, the block just begins to slide down the plane. What is the minimum force F applied parallel to the plane that would just make the block move up the plane?

    Solution

    The component of weight mg of the block along the inclined plane = M gsinθ

    The minimum frictional force to be overcome is also = M gsinθ

    To make the block just move up the plane the minimum force applied must overcome the component M gsinθ of gravitational force as well as the frictional force M gsin⁡θ = 2M gsin⁡θ

     

  • Question 9
    4 / -1

    A particle executing simple harmonic motion of amplitude 5 cm has a maximum speed of 31.4 cm/s. The frequency of its oscillation is:

    Solution

    The maximum speed of a particle executing SHM is

     

  • Question 10
    4 / -1

    0.73 g of organic compound on oxidation gave 1.32 g of carbon dioxide. The percentage of carbon in the given compound will be:

    Solution

     

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