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NEET Test 198

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NEET Test 198
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Weekly Quiz Competition
  • Question 1
    4 / -1

    Formic acid can be distinguished from acetic acid by reaction with:

    Solution

    Formic acid and acetic acid can be distinguished using 2,4-dinitrophenylhydrazine. 

    Formic acid is having aldehyde group, so it answers the above test. Forming yellow colour precipitate of 2,4-dinitro phenyl hydrazone. Whereas acetic acid does not.

     

     

  • Question 2
    4 / -1

    Which of the following causes dormancy of seeds?

    Solution

    In certain seeds, the dormancy of the seeds is due to the presence of certain germination inhibitors like coumarin, ferulic acid, abscisic acid, etc. These may be present in the endosperm, embryo, testa, or juice or pulp of the fruit.

     

  • Question 3
    4 / -1

    Greenhouses are often used for growing flowers, vegetables, fruits and transplants. Which among the following fungi is an obligate intracellular parasite found only from greenhouse cultures?

    Solution

    Completoria is a fungal genus in the monotypic family Completoriaceae, of the order Entomophthorales. Completoria is itself monotypic, containing a single species, Completoria complens. The species is rare, known only from greenhouse cultures where it grows as an obligate intracellular parasite of fern gametophytes.

     

  • Question 4
    4 / -1

    Molecular formula of Glauber's salt is-

    Solution

    Glauber’s salt is the decahydrate form of sodium sulfate. It is also known as mirabilite. The chemical formula of Glauber’s salt can be written as Na2SO4.10H2O. Glauber’s salt is known to be a vitreous mineral with a white or colorless appearance that is formed as an evaporite from brines containing sodium sulfate.

     

  • Question 5
    4 / -1

    A particle executing simple harmonic motion of amplitude 5 cm has a maximum speed of 31.4 cm/s. The frequency of its oscillation is:

    Solution

     

  • Question 6
    4 / -1

    A and B will respectively be:

    Solution

    Compound is β -hydroxy aldehyde hence the reaction is aldol addition. A and B can be known by retro aldol addition as follows:

     

  • Question 7
    4 / -1

    The proportion of the offsprings obtained from the cross AABBCC × AaBbCc will be completely heterozygous for all genes segregated independently will be:

    Solution

    As per Mendel's Law of Segregation, "alleles segregate randomly into gametes: When gametes are formed, each allele of one parent segregates randomly into the gametes, such that half of the parent's gametes carry each allele."

    The cross between parents with genotype produces the following progenies -

    Progeny with genotype heterozygous for all gene is 1 out of 8 types. Thus, probability is .

     

  • Question 8
    4 / -1

    What is the food habit of the original variety of Darwin's finches from which many other varieties are developed?

    Solution

    Darwin studied the flora and fauna of Galapagos Islands, a chain of islands on the west coast of South America. There he found an amazing range of creatures existing. He found that there were many varieties of small blackbirds in these islands which differed mainly in the shape of beaks and feeding habits. These varieties of small blackbirds were later called Darwin's Finches. After analyzing them, he realized that all of these varieties evolved on the same island itself and were not from separate areas. He conjectured that these varieties evolved from the original seedeating ancestor bird which was present in South America. Some of them flew to these islands and according to the needs of different environments, they developed different shapes of beaks and feeding habits. Some became insect-eating, some fruit-eating, some cactus eating, etc.

     

  • Question 9
    4 / -1

    The reflecting surface is given by  The co-ordinates of the point where a horizontal ray becomes vertical after reflection is:

    Solution

     

  • Question 10
    4 / -1

    In the circuit shown if the current for the diode is 20μA the potential difference across the diode is:

    Solution

    Since the diode is reversed biased, only drift current exists in the circuit which is 20μA.

    Potential drop across 15Ω resistor = 15Ω × 20μA

    = 300μV

    =0.0003V

    Potential difference across the diode = 4 − 0.0003

    = 3.99

    = 4V

     

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