Physics Test 71...

A 5A fuse wire can withstand a maximum power of 1W in circuit. Resistance of the fuse wire is:-

A cell of constant e.m.f. first connected to a resistance R₁ and then connected to a resistance R₂. If power delivered to resistances in the both cases are same then the internal resistance of the cell is:-

What should be the value of resistance R in the circuit shown in figure so that the electric bulb consumes the rated power?

For the arrangement of the potentiometer shown in the figure, the balance point is obtained at a distance 75 cm from A when the key K is open. The second balance point is obtained at 60 cm from A when the key K is closed. Find the internal resistance of battery E₁.

To convert a 800mV range milli voltmeter of resistance 40Ω into a galvanometer of 100 mA range, the resistance to be connected as shunt is:-

A voltmeter has resistance of 2000Ω and it can measure upto 2V. If we want to increase its range to 10V than the required resistance in series will be:-

A galvanometer of 25Ω resistance is shunted by a 2.5 Ω resistance. The part of the total current that passes through galvanometer is:-

Reading of the ammeter is:-

Equivalent resistance between a and b is:-

In the given circuit value of current I₃ is equal to:-