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Physics Test 73

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Physics Test 73
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Weekly Quiz Competition
  • Question 1
    4 / -1

    The equation of a projectile is y = 16x – x2/4. the horizontal range is :

    Solution

     

  • Question 2
    4 / -1

    A ball is thrown horizontally from a height of 20m. It hits the ground with a velocity three times its initial velocity. The initial velocity of ball is :-

    Solution

    2gh + vx2 = v2
    ∵ v = 3vx
    2gh + vx2 = 9vx2
    vx = 7 m/s

     

  • Question 3
    4 / -1

    The horizontal range of a projectile fired at an angle of 15o is 50 m. If it is fired with the same speed at an angle of 45o, its range will be

    Solution

    We know that,
    where, θ is angle of projection
    Given,        θ = 15o and R = 50 m

     

  • Question 4
    4 / -1

    A ball is thrown vertically upwards with an initial velocity of 5 m/sec from point P as shown. Q is point 10 m vertically below the point P. Then the speed of the ball at point Q will be : (take g = 10 m/sand neglect air resistance )

    Solution

    v1 = u2 + 2 as
    v2 = (5)2 + 2 × 10 × 10
    v2 = 25 + 200 ⇒ 225
    v = 15 m/sec

     

  • Question 5
    4 / -1

    A person, reaches a point directly opposite on the other bank of a flowing river, while swimming at a speed of 5 m/s at an angle of 120o with the flow. The speed of the flow must be :-

    Solution

     

  • Question 6
    4 / -1

    A man can swim at a speed of 3 km/hr in still water. He wants to cross a 500 m wide river flowing at 2 km/hr. He keeps himself at an angle 120º with river flow while swimming. the time taken to cross the river is :-

    Solution

     

  • Question 7
    4 / -1

    A particle is thrown vertically upwards & it returns to the starting point  after 10 sec. then its location after 7 sec. will be same as that after.

    Solution

     

  • Question 8
    4 / -1

    A particle's velocity changes from  m/s, to  m/s in 2 sec then acceleration of particle is :-

    Solution

     

  • Question 9
    4 / -1

    In a car race car A takes 't0' time less to finish than car B and passes the finishing point with velocity V0 more than car B. The cars  start from rest and travel. with constant acceleration a1 & a2. Then the ratio  is equal to :-

    Solution

     

  • Question 10
    4 / -1

    In 1-D motion due to constant positive acceleration :-

    Solution

    If velocity is in positive direction, along with acceleration then speed increases. If velocity is negative direction, opposite to acceleration then speed decreases.

     

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