Motion in a Straight Line Test 9

Result

Motion in a Straight Line Test 9

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following statements is incorrect?

A
Path length is a scalar quantity whereas displacement is a vector quantity.

B
The magnitude of displacement is always equal to the path length traversed by an object over a given time interval.

C
The displacement depends only on the end points whereas path length depends on the actual path followed.

D
The path length is always positive whereas displacement can be positive, negative and zero.

Solution

In one dimensional motion, the path length and magnitude of displacement are equal only if the object does not change its direction during the course of motion. In all other cases, the path length is greater than the magnitude of displacement.
Question 2
1 / -0

The numerical ratio of distance to displacement is

A
Always equal to one

B
Always less than one

C
always greater than one

D
equal or more than one

Solution

Distance ≥ |Displacement|
Question 3
1 / -0

Which of the following statements is incorrect?

A
Displacement is independent of the choice of origin of the axis.

B
Displacement may or may not be equal to the distance travelled.

C
When a particle returns to its starting point, its displacement is not zero.

D
Displacement does not tell the nature of the actual motion of a particle between the points.

Solution

When a particle returns to it's initial position, Initial and final positions will be same therefore net displacement of the particle is zero. Hence the given statement is false.
Question 4
1 / -0

If a man goes 10 m toward north and 20 m toward east, then his displacement is

A
22.5 m

B
25 m

C
25.5 m

D
30 m

Solution
Question 5
1 / -0

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:

A
21 s

B
29 s

C
31 s

D
37 s

Solution

Displacement in first eight steps = (5 - 3) m = 2 m
Time taken for first eight steps = 8 s
Time taken by the drunkard to cover first 6 m of journey = 8/2 * 6 = 24 s
If the drunkard takes 5 steps more, he will fall into the pit. So the time taken by the drunkard to cover last five steps = 5 s
Total time taken = 24 s + 5 s = 29 s