Gravitation Test

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Gravitation Test - 10

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Weekly Quiz Competition

Question 1
1 / -0

India’s first artificial satellite was:

A
Sputnik

B
Rohini

C
Insat

D
Aryabhatta

Solution

India's first artificial satellite was Aryabhata. Launched by soviet union on 19 April 1975
Question 2
1 / -0

According to Kepler’s Third Law:

A
T² ∝ R³

B

C

D
T³ ∝ R²
Question 3
1 / -0

Weightlessness is:

A
a situation in which the effective weight of the body becomes zero

B
a situation in which the effective weight of the body becomes 10N

C
a situation in which the effective weight of the body becomes 9.8N.

D
a situation in which the effective mass of the body becomes zero

Solution

Weight becomes zero in a freefall or when the total force on your body is zero. For example, in a freely falling lift the contact force on your body is zero, so the weighing machine would show zero reading. So you are weightless.
Question 4
1 / -0

Different planets have different escape velocities because:

A
different planets have different atmosphere

B
they have different distances from sun

C
escape velocity depends on the body that has to escape the atmosphere of the planet

D
they have different masses and sizes

Solution

The formula for calculating the escape velocity from the surface of a celestial body (e.g. a planet) is:

where G is the universal gravitation constant, M is the planet’s mass and R is its radius. Different planets have different mass and radius - and therefore different escape velocity.
Question 5
1 / -0

Kepler’s second law states that the straight line joining the planet to the sun sweeps out equal areas in equal time. The statement is equivalent to saying that:

A
longitudnal acceleration is zero

B
total acceleration is zero

C
transverse acceleration is zero

D
radial acceleration is zero

Solution

According to the second law the orbital radius and angular velocity of the planet in the elliptical orbit will vary. The planet travels faster when closer to the Sun, then slower when farther from the Sun. Hence we can say that the transverse acceleration is zero while radial and longitudinal accelerations are not zero.
Question 6
1 / -0

A satellite which appears to be at a fixed position at a definite height to an observer is called:

A
Geostationary satellite and geosynchronous satellite

B
Polar satellite

C
Geostationary satellite

D
Geosynchronous satellite

Solution

As the relative velocity of the satellite with respect to the earth is zero, it appears stationary from the Earth surface and therefore it is called is geostationary satellite or geosynchronous satellite.
Question 7
1 / -0

The squares of the periods of revolution of the planets are proportional to the ___________of their semimajor axis of its orbit.

A
sqaures

B
sqaures root

C
cube

D
cube roots

Solution

The Law of Periods: The square of the period of any planet is proportional to the cube of the semimajor axis of its orbit.
Question 8
1 / -0

Which is untrue about orbital velocity?

A
increases with the decrease in height of satellite

B
depends on mass and radius of planet around which it revolves

C
it is independent of mass of satellite

D
decreases with an increase in radius of orbit

Solution

1.Orbital velocity of satellite is independent of mass of the satellite
2.It decreases with increase in the radius of the orbit and with increase in the height of the satellite
3.it depends on the mass and radius of the planet about which the satellites revolves.
4.The angular momentum of a satellite of mass m moving with velocity vo in an orbit of radius r=(R+h) is given by L=√GMm²r
Question 9
1 / -0

A satellite moves in a circular orbit around earth. The radius of this orbit is one half that of moon’s orbit. The satellite completes one revolution in:

A
(2) ^3/2 lunar month

B
(2) ³ lunar month

C
(2) ^-^3/2 lunar month

D
(2)^1/2 lunar month

Solution

The time period of revolution of the moon around the earth = 1 lunar month.
► T_s/T_m = (r_s/r_m)^3/2= (1/2)^3/2
► T_s = (2)^-^3/2 lunar month
Question 10
1 / -0

Kepler’s law of areas can be understood as a consequence of:

A
conservation of angular momentum

B
conservation of mass

C
conservation of energy

D
conservation of linear momentum

Solution

Conservation of angular momentum:
L= 2m dA/dt

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Gravitation Test - 10

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Gravitation Test - 10

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SHARING IS CARING

Question 1

Sputnik

Rohini

Insat

Aryabhatta

Solution

Question 2

T2 ∝ R3

T3 ∝ R2

Question 3

a situation in which the effective weight of the body becomes zero

a situation in which the effective weight of the body becomes 10N

a situation in which the effective weight of the body becomes 9.8N.

a situation in which the effective mass of the body becomes zero

Solution

Question 4

different planets have different atmosphere

they have different distances from sun

escape velocity depends on the body that has to escape the atmosphere of the planet

they have different masses and sizes

Solution

Question 5

longitudnal acceleration is zero

total acceleration is zero

transverse acceleration is zero

radial acceleration is zero

Solution

Question 6

Geostationary satellite and geosynchronous satellite

Polar satellite

Geostationary satellite

Geosynchronous satellite

Solution

Question 7

sqaures

sqaures root

cube

cube roots

Solution

Question 8

increases with the decrease in height of satellite

depends on mass and radius of planet around which it revolves

it is independent of mass of satellite

decreases with an increase in radius of orbit

Solution

Question 9

(2) 3/2 lunar month

(2) 3 lunar month

(2) -3/2 lunar month

(2)1/2 lunar month

Solution

Question 10

conservation of angular momentum

conservation of mass

conservation of energy

conservation of linear momentum

Solution

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T² ∝ R³

T³ ∝ R²

(2) ^3/2 lunar month

(2) ³ lunar month

(2) ^-^3/2 lunar month

(2)^1/2 lunar month