Quantitative and Numerical Ability Test

Result

Quantitative and Numerical Ability Test - 2

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Weekly Quiz Competition

Question 1
1 / -0

A and B enter into a partnership business with capital investment in the respective ratio of 27: 40. At the end of 7 months, 'A' withdraws completely from the business. If 'A' and 'B' receive profit in the respective ratio of 21: 40, find out for how long was "B's capital used?

A
8 months

B
9 months

C
6 months

D
10 months

E
12 months

Solution

Let the capital of B was used for ‘x’ months. So we have

27*7/40*x = 21 / 40 ⇒ x = 9 months
Question 2
1 / -0

Machine A and machine B are each used to manufacture 660 bolts. It takes machine A 10 hours more than machine B to produce 660 bolts. Machine B produces 10 percent more bolts per hour than machine A. How many bolts per hour can machine A produce?

A
6

B
6.6

C
60

D
100

E
110

Solution
Question 3
1 / -0

A thief goes away in a car at a speed of 60 kmph. A cop starts chasing the thief after 15 minutes in a car at a speed of 80 kmph. After how much time will cop overtake the theif?

A
30 minutes

B
36 minutes

C
40 minutes

D
45 minutes

E
50 minutes

Solution

In 15 minutes thief will be 15 Km away . There will be a gap of 15 Km between thief and police . This gap will be covered with a relative speed of 80 -60=20 Km/h .So thief will be overtaken in 15/20 hours= 45 minutes.

So option D.
Question 4
1 / -0

The average of four positive integers is 72.5. The highest integer is 117 and the lowest integer is 15. The difference between the remaining two integers is 12. Which is the higher of these two remaining integers?

A
73

B
84

C
70

D
Cannot be determined

E
None of these

Solution
Question 5
1 / -0

A man while returning from his factory, travels 2/3 of the distance by bus, 3/4 of the rest by car and remaining by foot. If he travels 2 km on foot, find the distance covered by him.

A
24 km

B
22 km

C
28 km

D
26 km

E
None of these

Solution
Question 6
1 / -0

A square is drawn inside a square of perimeter 96 cm by leaving a gap of 1 cm all around. A third square is drawn inside the second square by leaving a gap of 1 cm all around and so on. What is the ratio of the area of the eighth square to the area of the smallest square?

A
36

B
5

C
12

D
25

E
18

Solution

The side of the 1st square is 24. Since there is a gp of 1 all around, the side of the second square is 22. The sides of subsequent squares keep reducing by 2 till the side of the smallest square is 2. The side of the 8th square is 24 – (7 × 2) = 10. The ratio of areas is 100:4 = 25.
Question 7
1 / -0

Supply the missing digit in the number 3_930. The number is divisible by 3 and is divisible by only one of 11, 9 and 7 but is not divisible by 19. The number is:

A
3

B
6

C
9

D
3 or 9

E
None of these

Solution

Using the divisibility test of 3, we can put

0, 3, 6, 9 in the missing place.

Checking these one by one, we get 33930 as divisible by only 9 and not 19, and 39930 divisible by 11 and not by 19.

Hence 3 or 9 can be the missing digits.
Question 8
1 / -0

2401 × 35² × 25⁴ / 7³ = 5^m × 7ⁿ, what are the value of m and n?

A
m = 5, n = 3

B
m = 10, n = 5

C
m = 5, n = 6

D
m = 5, n = 10

E
m = 10, n = 3

Solution

We have 2401 × 35²× 25⁴/ 73 = 5^m × 7ⁿ

⇒ 7⁴ × 7² × 5² × 5⁸/7³= 5^m × 7ⁿ

⇒ 7³ × 5¹⁰ = 5^m × 7ⁿ

⇒ m = 10 and n = 3.
Question 9
1 / -0

The value of each of a set of coins varies as the square of its diameter, if its thickness remains constant, and it varies as the thickness, if the diameter remains constant. If the diameter of two coins are in the ratio 4 : 3, what should be the ratio of their thickness be, if the value of the first is four times that of the second?

A
16 : 9

B
9 : 4

C
9 : 16

D
4 : 9

E
None of these

Solution
Question 10
1 / -0

The present age of Charu is twice the present age of Prerna. Harsh is 4 years older to Charu. If the sum of the present ages of Prerna, Charu and Harsh is 74 years, what is the present age of Harsh (in years)?

A
14

B
36

C
34

D
28

E
32

Solution

Let the age of Prerna is x years. So the age of Charu is 2x and of Harsh is 2x + 4. Now x + 2x + 2x + 4 = 74 ⇒ 5x = 70 ⇒ x = 14. So the age of Harsh is 2x + 4 = 2 × 14 + 4 = 32 years.

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Re-Attempt Weekly Quiz Competition

Quantitative and Numerical Ability Test - 2

Result

Quantitative and Numerical Ability Test - 2

Score

-

Rank

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SHARING IS CARING

Question 1

8 months

9 months

6 months

10 months

12 months

Solution

Question 2

6

6.6

60

100

110

Solution

Question 3

30 minutes

36 minutes

40 minutes

45 minutes

50 minutes

Solution

Question 4

73

84

70

Cannot be determined

None of these

Solution

Question 5

24 km

22 km

28 km

26 km

None of these

Solution

Question 6

36

5

12

25

18

Solution

Question 7

3

6

9

3 or 9

None of these

Solution

Question 8

m = 5, n = 3

m = 10, n = 5

m = 5, n = 6

m = 5, n = 10

m = 10, n = 3

Solution

Question 9

16 : 9

9 : 4

9 : 16

4 : 9

None of these

Solution

Question 10

14

36

34

28

32

Solution

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Question Analysis