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Area Related to Circle Test - 5

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Area Related to Circle Test - 5
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  • Question 1
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    Anu prepares two playgrounds for pets, one is circular and another is rectangular. The areas of the circular and rectangular playgrounds are 22,176 cm2 and 55,440 cm2, respectively. She wants to create a fence around the playgrounds. If the length of the rectangular playground is 13.86 m, then how much more wire does she have to buy for the rectangular playground than for the circular playground?

    Solution

    Area of the circular playground = πr2
    22,176 = πr2

    22,176 × 7/22 = r2
    7056 = r2
    r = 84 cm

    Amount of wire used for the circular playground = Circumference of the circle = 2πr
    = 2 × 22/7 × 84

    = 528 cm --- (1)
    13.86 m = 13.86 × 100 = 1386 cm
    Area of the rectangular playground = l × b

    55,440 = 1386 × b
    55,440 ÷ 1386 = b
    40 cm = b

    Perimeter of the rectangle = 2(l + b)
    = 2(1386 + 40)
    = 2(1426)
    = 2852 cm --- (2)

    Length of the extra wire for rectangular playground = 2852 – 528 [from equations (1) and (2)] = 2324 cm
    2324 cm = 2324 ÷ 100 = 23.24 m

     

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