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Pair of Linear Equation in Two Variables Test - 1

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Pair of Linear Equation in Two Variables Test - 1
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  • Question 1
    1 / -0

    The sum of the digits of a two-digit number is 6. Also, twice of this number is 6 more than the number obtained by reversing the order of the digits. Find the number.

    Solution

    Let the unit digit and tens digit of the number be x and y respectively.
    Then, the number = 10y + x
    Number after reversing the digits = 10x + y
    According to the given information, x + y = 6 ..........(i)
    2 ( 10y + x ) = 6 + ( 10x + y )
    ⇒ 20y + 2x = 6 + 10x + y
    ⇒ 20y - y + 2x - 10x = 6
    ⇒ 19y - 8x = 6 ..........(ii)

    From, eq (i), we get
    x = 6 - y
    Now putting this in eq (ii), we get
    19y - 8 ( 6 - y ) = 6
    ⇒ 19y - 48 + 8y = 6
    ⇒ 27y = 6 + 48
    ⇒ 27y = 54
    ⇒ y = 2

    Thus, substituting it back in eq (i)
    x + 2 = 6
    x = 6 - 2
    x = 4
    Thus, the required number is 10y + x = 10 (2) + 4 = 20 + 4 = 24

     

  • Question 2
    1 / -0

    Arya starts his job with certain monthly salary and earns a certain increment every year. If his salary was Rs. 6,300 after 6 years of service and Rs. 7,200 after 12 years, find his initial salary and annual increment respectively.

    Solution

    Let the annual increment be Rs. y. And initial salary be Rs. x.
    According to the question, x + 6y = 6300 ...............(i)And x + 12y = 7200 ...........(ii)
    Subtracting (ii) from (i) we have x + 6y - x + 12 y = 6300 - 7200 -6y = - 900
    6y = 900
    y = 900 ÷ 6
    = 150

    Putting the value of y in (i) we have x + 6y = 6300
    x + 6 (150) = 6300
    x + 900 = 6300
    x = 6300 - 900
    x = 5400

     

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