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Polynomials Test - 2

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Polynomials Test - 2
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  • Question 1
    1 / -0

    If x3 + ax2 + bx + 12 leaves remainder 4 when divided by (x - 1), which of the following is the value of a + b?

    Solution

    Let p(x) be x3 + ax2 + bx + 12
    g(x) = x - 1
    On division of p(x) by g(x), remainder = 4
    Now, g(x) is linear.
    So, g(x) = 0
    x - 1 = 0
    x = 1
    Now, (+1)3 + a (+1)2 + b (+1) + 12 = 4
    Or, 1 + a + b + 12 = 4
    a + b + 13 = 4
    a + b = 4 - 13
    a + b = -9

     

  • Question 2
    1 / -0

    If the weights of two different quantities are (3x3 - 6x2 - 4x + 8) kg and (5x3 - 10x2 + 2x - 4) kg, then what is the biggest measure that can weigh both the quantities?

    Solution

    Weights of two different quantities:
    (3x3 - 6x2 - 4x + 8) kg and (5x3 - 10x2 + 2x - 4) kg

    Weight of the first quantity = (3x3 - 6x2 - 4x + 8) kg
    = 3x2(x - 2) - 4(x - 2)
    = (x - 2)(3x2 - 4)

    Weight of the second quantity = (5x3 - 10x2 + 2x - 4) kg
    = 5x2(x - 2) + 2(x - 2)
    = (x - 2)(5x2 + 2)
    Therefore, required measure is the H.C.F. of both the weights, i.e (x - 2) kg.

     

  • Question 3
    1 / -0

    The radius and height of a cylindrical pipe are (5x2 - 27x) m and (3x2 - 20x) m, respectively. Find the surface area of the pipe which is open from both the sides when x = √(49).

    Solution

    Let the radius of the pipe be r and the height be h.

    r = (5x2 - 27x) m

    h = (3x2 - 20x) m

    When x = √(49)= 7;

    r = (5(7)2 - 27(7)) m = 245 - 189 = 56 m

    h = (3(7)2 - 20(7)) m = 147 - 140 = 7 m

    Surface area (open cylindrical pipe) = 2πrh

    = 2 × 22/7 × 56 × 7 = 2 × 22 × 8 × 7 = 2464 m2

     

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