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IMO - Mock Test - 5

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IMO - Mock Test - 5
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Find out the pattern followed in the series given below:

    15, 16, 19, 28, 55, 136

    Solution

    The pattern is as follows:
    Triple the difference each time.
    16 - 15 = 1
    19 - 16 = 3; (1 x 3 = 3)

     

  • Question 2
    1 / -0

    If + means x, - means ÷, ÷ means + and x means -, then find the value of 25 + 5 x 25 - 25.

    Solution

    25 + 5 x 25 - 25 = ?

    25 × 5 - 25 ÷ 25

    = 125 - 1 = 124

     

  • Question 3
    1 / -0

    Sophie ranked 9 in a class of 55 students. What was the rank of Sophie from the bottom?

    Solution

    If a student is at rank 9 in a class of 55 students, to get the rank from the bottom, we have to subtract 9 from 55, which gives 46.
    After that, add 1 for that student.

     

  • Question 4
    1 / -0

    Anup went shopping on 5th April, which was a Friday, and decided to go again after 5 days. What day would it be on which Anup went shopping again?

    Solution

    Day on which Anup went shopping = Friday

    Next visit would be after 5 days, that is, after Saturday, Sunday, Monday, Tuesday and Wednesday, which is a Thursday.

     

  • Question 5
    1 / -0

    If "COMPUTER" is coded as "DNNOVSFQ", then how will you code "BOTTLE" in the same way?

    Solution

    C + 1 = D
    O - 1 = N
    M + 1 = N
    P - 1 = O
    U + 1 = V
    T - 1 = S
    E + 1 = F
    R - 1 = Q
    In the same way, "BOTTLE" is coded as "CNUSMD".

     

  • Question 6
    1 / -0

    The length of a rectangle is 5 m less than four times its width. If the perimeter of the rectangle is 180 m, what is its area?

    Solution

    Let the width of the rectangle be x.
    So,
    Length = 4x – 5
    Perimeter = 2(4x – 5 + x) = 180
    5x – 5 = 90
    5x = 95
    ⇒ x = 95/5 = 19 
    Length = 4 × 19 – 5 = 71 m
    Width = 19 m
    Area = 71 × 19 = 1349 m2

     

  • Question 7
    1 / -0

    What would be the perimeter of the square if the side of the square is equal to the breadth of the rectangle, whose length is 22 cm, which is twice its breadth?

    Solution

    Length of the rectangle = 2(breadth)

    22 = 2 x breadth

    Breadth = 22/2

    Breadth = 11 cm

    Side of the square = Breadth of the rectangle

    Side of the square = 11 cm

    Perimeter of the square = 4(side)

    = 4 x 11 = 44 cm

     

  • Question 8
    1 / -0

    What is the value of x in 7(3x + 2) – 4(6x – 1) = 7(x + 2) – 7(5x – 6) + 12?

    Solution

    7(3x + 2) - 4(6x - 1) = 7(x + 2) - 7(5x - 6) + 12
    21x + 14 - 24x + 4 = 7x + 14 - 35x + 42 + 12
    -3x + 18 = -28x + 68
    25x = 50
    x = 2

     

  • Question 9
    1 / -0

    Find the additive inverse of -5/17.

    Solution

    The additive inverse of -5/17 is 5/17. For a fraction, the definition of additive inverse remains the same. If a number is positive, then the additive inverse will be the negative version of the same number. The opposite is also true. If a number is negative, then the additive inverse will be the positive version of that same number.

     

  • Question 10
    1 / -0

    A rectangle with sides 7 cm and 4 cm has area 5 times larger than another rectangle. Find the width of smaller rectangle if its length is 2.1 cm.

    Solution

    Area of larger rectangle = 7 × 4 = 28 cm2

    Area of smaller rectangle = 28/5 sq. cm = 5.6 sq. cm

    Length of smaller rectangle = 2.1 cm

    Width of smaller rectangle = 5.6/2.1 = 2.67 cm

     

  • Question 11
    1 / -0

    The area of a rectangular field is 350 ft2. Its dimensions are in the ratio 2 : 7. What is the length of the fencing of the field?

    Solution

    Let the length and width of the rectangular field be 7x and 2x, respectively.
    So,
    Area = L × W
    350 = 7x × 2x
    ⇒ 14x2 = 350
    ⇒ x2 = 25
    x = 5 ft
    ⇒ Length = 7x = 7 × 5 = 35 ft
    Width = 2x = 2 × 5 = 10 ft
    Perimeter = 2(L + W) = 2(35 + 10) = 90 ft

     

  • Question 12
    1 / -0

    If 384a is divisible by 9, then 'a' is

    Solution

    3 + 5 + 4 + a = 18 [For 384a to be divisible by 9, the sum of all digits must be divisible by 9]
    Or, 18 – 15 = a
    Or, a = 3

     

  • Question 13
    1 / -0

    When rounded off to the nearest thousands, I become 31,000. Find me out of the following.

    Solution

    31,312 round down to 31,000.

     

  • Question 14
    1 / -0

    The difference between the measures of two complementary angles is 20°. Find the measure of both the angles.

    Solution

    Let one angle be x.
    Complementary angle is ⇒ 90 – x
    (90 – x) – x = 20
    90 – 2x = 20
    70 = 2x
    x = 35
    90 – x = 90 – 35 = 55
    Angles are 35°, 55°.

     

  • Question 15
    1 / -0

    Write the Roman Numeral for 567?

    Solution

    D – 500, LX – 60, VII – 7

    567 = 500 + 60 + 7 = DLXVII

     

  • Question 16
    1 / -0

    Two angles in a triangle are in the ratio 4 : 5. If the sum of these angles is equal to the third angle, then the third angle is _____.

    Solution

    Let the three angles be 4x, 5x and 9x.
    Now, according to the question:
    4x + 5x + 9x = 180°
    18x = 180°
    x = 10°
    Third angle = 90°

     

  • Question 17
    1 / -0

    Find the difference between the smallest 8-digit number and the largest 5-digit number.

    Solution

    Smallest 8-digit number = 10000000
    Largest 5-digit number = 99999
    Difference = 10000000 – 99999
    = 9900001

     

  • Question 18
    1 / -0

    In an election, there were two candidates A and B. A got 72% votes and was elected by a margin of 11,000 votes. The total number of votes polled was

    Solution

    Let the total number of votes polled be x.

    So, A got 0.72x.
    And, B got x – 0.72x = 0.28x

    Difference = 0.72x – 0.28x = 0.44x

    According to the question:
    0.44x = 11,000
    x = 25,000

     

  • Question 19
    1 / -0

    Sam scored 236 marks out of 280 in his assessments. Find his percentage score.

    Solution

    Marks scored by Sam = 236
    Total marks = 280
    % marks of Sam = 236/280 × 100
    = 84.28%

     

  • Question 20
    1 / -0

    In a firm, 30% of the employees are female. Find the number of female employees if number of male employees are 280.

    Solution

    Let the total number of employees be x.

    So, 30% of x are females. ----- (1)

    And 70% of x are males. ------ (2)

    If the number of males is 280, then 280 = 70% of x

    or 280/0.7 = x

    x = 400

    So, the number of females = 30% of 400 = 0.3 × 400 = 120

     

  • Question 21
    1 / -0

    Area of house A is 2456 m2, area of house B is 89,632 m2, and area of house C is 5632 m2. What is the difference between the total area of houses A and C together, and the area of house B?

    Solution

    Total of area of houses A and C = 2456 m2 + 5632 m= 8088 m2

    The required difference = 89,632 m- 8088 m= 81,544 m2

     

  • Question 22
    1 / -0

    A rectangular hotel room is 13 m x 20 m. The owner of the hotel wants to re-carpet the room with carpet that costs Rs. 1450 per sq.m. How much will it cost to re-carpet the room?

    Solution

    Area of a rectangle = Length × Width

    Area of the rectangular hotel room = 13 x 20 = 260 m2

    Now, total cost to re-carpet the room = Rs. 260 x 1450 = Rs. 3,77,000

     

  • Question 23
    1 / -0

    In a kitchen garden, a snail covers 230 cm in 1 minute, while Ankit covers or walks 4 m in just 30 seconds. What is the total distance covered by both of them together in one minute?

    Solution

    Distance covered by the snail in one minute = 230 cm
    Distance covered or walked by Ankit in 30 seconds = 4 m
    Distance covered by Ankit in one minute or 60 seconds = 8 m
    We know that 1 m = 100 cm, so 230 cm will be 230 ÷ 100 = 2.3 m
    Now, the total distance covered in metres = 8 m + 2.3 m = 10.3 m

     

  • Question 24
    1 / -0

    Pharrell invited 50 friends on her birthday party. She thought of serving snacks and a soft drink and bought 4 bottles of soft drink of volume 2 litres each, and 1 bottle of soft drink of volume 1 litre. What volume of soft drink will be served to each person if it is distributed among 50 of her friends equally?

    Solution

    Total volume of soft drink available = (4 × 2 + 1 × 1) L = 9 L

    Distributing 9 L of soft drink among 50 of her friends =9/50 = 0.18 L = 180 mL

    So, each of her friends will be served 180 mL of soft drink in the party.

     

  • Question 25
    1 / -0

    The height of a tower is 50 m. Two-fifth of the tower is coloured in red and of the remaining portion, again two-third is coloured in green and the remaining in white. Find out the length of the portion coloured in white?

    Solution

    Height of the tower = 50 m

    2/5 of the total height = 20 m, which is coloured in red

    Remaining portion = 50 - 20 m = 30 m

    2/3 of the total height = 2/3 of 30 m = 20 m, which is coloured in green

    Remaining portion = 30 - 20 m = 10 m, which is coloured in white

     

  • Question 26
    1 / -0

    Price of a cake is Rs. 230 and price of an ice-cream is Rs. 55. How much will a student have to spend to buy 3 ice creams and 2 cakes?

    Solution

    Price of a cake = Rs. 230

    Price of 2 cakes = Rs. 230 × 2 = Rs. 460

    Price of an ice-cream = Rs. 55

    Price of 3 ice-creams = Rs. 55 × 3 = Rs. 165

    Total money needed to buy both the things = Rs. 460 + Rs. 165 = Rs. 625

     

  • Question 27
    1 / -0

    On a trip, 560 students went to Shimla. Out of the total students, the ratio of the boys to girls was 3 : 4. What is the difference between the numbers of girls and boys?

    Solution

    Total number of students = 560

    Number of boys = 3/7 of 560 = 240

    Number of girls = 4/7 of 560 = 320

    Difference between the numbers of boys and girls = 320 - 240 = 80

     

  • Question 28
    1 / -0

    Which of the following properties is not true regarding a rhombus?

    Solution

    All the sides in a rhombus are the same or congruent. So, the property mentioned in option 1 is not correct about a rhombus.

     

  • Question 29
    1 / -0

    A Private Limited Company, in its first year, makes a profit of Rs. 1,00,420 and in the second year, it doubles the profit made in the first year, and in the third year, it doubles the profit made in the second year. How much profit has the company made in its three years?

    Solution

    Profit made in the first year = Rs. 1,00,420
    Profit made in the second year = Rs. 1,00,420 × 2 = Rs. 2,00,840
    Profit made in the third year = Rs. 1,00,420 × 4 = Rs. 4,01,680
    Total profit made in three years = Rs. 1,00,420 + 2,00,840 + 4,01,680 = Rs. 7,02,940

     

  • Question 30
    1 / -0

    Sham bought 5 white balls. Then he bought red balls two more than white balls, and pink balls twice the number of red balls. The costs of a white ball, a red ball and a pink ball are Rs. 50, Rs. 55, and Rs. 65 respectively. How much did he pay to the shopkeeper?

    Solution

    There are 5 white balls, so the cost of 5 white balls is 5 × 50 = Rs. 250
    Number of red balls is two more than that of white balls, that means 5 + 2 = 7 red balls, so the cost of 7 red balls is Rs. 55 × 7 = Rs. 385
    Number of pink balls is twice that of red balls, that means 7 × 2 = 14 pink balls, so the cost of 14 pink balls is Rs. 65 × 14 = Rs. 910

    Therefore, total cost of all the balls is Rs. 250 + 385 + 910 = Rs. 1545

     

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