IMO - Mock Test

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IMO - Mock Test - 1

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Weekly Quiz Competition

Question 1
1 / -0

Complete the sequence:

16, 72, 192, 400, ____?

A
592

B
208

C
720

D
576

Solution

4 × 2² = 16

8 × 3² = 72

12 × 4² = 192

16 × 5² = 400

20 × 6² = 720
Question 2
1 / -0

If A means '+' B means '-', C means '÷' and D means 'x', find the value of 36 C 2 D 3 A 14 B 7 A 2

A
15

B
34

C
59

D
63

Solution

Using BODMAS ,

36 ÷ 2 × 3 + 14 - 7 + 2

= 54 + 14 - 7 + 2

= 68 - 7 + 2 = 61 + 2 = 63
Question 3
1 / -0

Find the wrong term in the given series:

1, 6, 13, 28, 33, 46

A
28

B
13

C
6

D
1

Solution

Each of the numbers is a result of subtraction of 3 from 2², 3², 4², 5²and6²respectively.
1 = 2² - 3
6 = 3² - 3
13 = 4² - 3
33 = 6² - 3
46 = 7² - 3
But, as 5²is 25 and 25 - 3 = 22, but in the series it is 28.
Question 4
1 / -0

In the following question, four numbers are given. Three of them are alike in some way. Find the odd one out.

A
63

B
17

C
13

D
23

Solution

Except option (1), all the others are prime numbers.
Question 5
1 / -0

Study the following arrangement carefully and answer the question given below.

B M % R 3 J @ K © D F 6 9 W 4 * N E P 2 $ A Y 5 I Q Z # 7 U G

Which of the following is sixth to the left of the twentieth from the left end of the above arrangement?

A
J

B
Q

C
W

D
E

Solution

Twentieth from the left end is '2'.
Sixth to the left of 2 is 'W'.
Question 6
1 / -0

Kyle started a new business in stationery goods. He found that, among the goods that he bought for his shop, out of 500 correction tapes 35 were not working properly. Which of the following gives you the probability of picking the correction tape which is working properly?

A
93/100

B
47/100

C
27/100

D
7/100

Solution

Total number of correction tapes = 500
Correction tapes not in working condition = 35
Correction tapes which are working properly = 465
Probability of picking the correction tape which is working properly = 465/500 = 93/100
Question 7
1 / -0

What is the perpendicular distance of the point (- 4, 3) from the x-axis?

A
7 units

B
4 units

C
3 units

D
2 units

Solution

The point (- 4,3) will lie in the 4th quadrant. The y coordinate is 3. So, the distance from that point to the x axis will be 3 units.
Question 8
1 / -0

What will be the remainder when p³ + p² - 2p + 5 is divided by p - 3?

A
- 7

B
25

C
35

D
47

Solution

Following the remainder theorem, remainder p(3) = 27 + 9 - 6 + 5 = 35
Question 9
1 / -0

If 09/12/2001 happened to be Sunday, then 09/12/1971 was

A
Wednesday

B
Tuesday

C
Saturday

D
Thursday

Solution

In 30 years from 1971 to 2001, number of odd days = 30 + 8 (from leap years) = 38 odd days
It gives 3 odd days after being divided by 7.
So, December 9, 1971 is Thursday (three days before Sunday).
Question 10
1 / -0

Jack bought 40 boxes of oranges and 20 boxes of guavas. He picked one box at random. What is the probability that the box is of guavas?

A
1/3

B
1/2

C
2/3

D
None of these

Solution

Number of boxes of oranges = 40
Number of boxes of guavas = 20
Favourable outcomes = 20
Total outcomes = 60
Required probability = 20/60 = 1/3
Question 11
1 / -0

The present ages of Tom, Harry and Sam are in the ratio 3 : 4 : 5. The sum of their ages 5 years ago was 21. Find the product of Tom and Sam's present ages.

A
108

B
135

C
150

D
180

Solution

Let the present ages of Tom, Harry and Sam be 3x yrs, 4x yrs, 5x yrs.

5 years ago,

(3x - 5) yrs + (4x - 5) yrs + (5x - 5) yrs = 21 yrs

(12x - 15)yrs = 21 yrs

12x = 36

x = 3

The present ages will be:

Tom = 9 years

Harry = 12 years

Sam = 15 years

Product = 9 × 15 = 135.
Question 12
1 / -0

The speed of a boat in still water is 10 m/s and that of the stream is 6 m/s. If the boat is moving upstream and then downstream, what is the ratio of the time taken to cover a particular stretch of distance in each direction, respectively?

A
4 : 1

B
1 : 4

C
2 : 1

D
2 : 3

Solution

It is given that the distance travelled in each direction is the same.

The effective speeds are in the ratio (10 - 6) : (10 + 6) = 1 : 4.

∴The time taken to travel upstream and downstream is in the ratio (1/1) : (1/4) = 4 : 1.
Question 13
1 / -0

The lengths of the sides of a rectangular park are in the ratio 3 : 2. If its area is 3750 sq. metres, then the cost of fencing it at the rate of Rs. 5 per metre is

A
Rs. 3125

B
Rs. 3750

C
Rs. 1875

D
Rs. 1250

Solution

Let the lengths of the sides of the rectangle be 3x and 2x m.
Area = 6x² m² = 3750 m²
x² = 625
⇒ x = 25
Perimeter = 2 × (3x + 2x) m = 2 × 5x m = 250 m
Cost of fencing = 250 m × Rs. 5/m = Rs. 1250
Question 14
1 / -0

A bag contains 89 coins of 50 paisa and 25 paisa. If the total worth of these coins is Rs. 28.50, find the number of 25 paisa coins and 50 paisa coins.

A
25 and 64

B
64 and 25

C
54 and 35

D
35 and 54

Solution

Let the number of 50 paise coins be b.

Thus, the number of 25 paise coins = (89 - b)

Now, total amount = 50b + (89 - b) 25 = 2850

Or, b = 25

89 - b = 89 - 25 = 64

the number of 25 paise coins = 64 and number of 50 paise coins = 25.

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Re-Attempt Weekly Quiz Competition

IMO - Mock Test - 1

Result

IMO - Mock Test - 1

Score

-

Rank

-

SHARING IS CARING

Question 1

592

208

720

576

Solution

Question 2

15

34

59

63

Solution

Question 3

28

13

6

1

Solution

Question 4

63

17

13

23

Solution

Question 5

J

Q

W

E

Solution

Question 6

93/100

47/100

27/100

7/100

Solution

Question 7

7 units

4 units

3 units

2 units

Solution

Question 8

- 7

25

35

47

Solution

Question 9

Wednesday

Tuesday

Saturday

Thursday

Solution

Question 10

1/3

1/2

2/3

None of these

Solution

Question 11

108

135

150

180

Solution

Question 12

4 : 1

1 : 4

2 : 1

2 : 3

Solution